Wie Eliff Anweisung Verwendung reduzieren?

Question

Wenn ich ein Programm mache, das Sie zum Übersetzen von Wörtern legiert, gibt es eine Möglichkeit, elif nicht jeden Zeh zu verwenden und einfach nur Wörter zu übersetzen. Das habe ich jetzt bekommen!

print("English to Exrian Dictionary") 

search = input("Enter the word you would like to translate: ").lower() 

if search == "ant": 
    print("Ulf") 
elif search == "back": 
    print("Zuwp") 
elif search == "ban": 
    print("Zul") 
elif search == "bat": 
    print("Zuf") 
elif search == "bye": 
    print("Zio") 
elif search == "wumohu": 
    print("Camera") 
elif search == "car": 
    print("Wuh") 
elif search == "carrot": 
    print("Wuhhef") 
elif search == "cat": 
    print("Wuf") 
elif search == "doctor": 
    print("vewfeh") 
elif search == "dog": 
    print("Ves") 
elif search == "duck": 
    print("Vawp") 
elif search == "egg": 
    print("Oss") 
elif search == "enter": 
    print("Olfoh") 
elif search == "experiment": 
    print("Oxkohymolf") 
elif search == "fat": 
    print("Tuf") 
elif search == "flower": 
    print("Tnecoh") 
elif search == "goal": 
    print("Seun") 
elif search == "goat": 
    print("Seuf") 
elif search == "hand": 
    print("Rulv") 
elif search == "hat": 
    print("Ruf") 
elif search == "hello": 
    print("Ronne") 
elif search == "hello": 
    print("Ronne") 
elif search == "house": 
    print("Reago") 
elif search == "hello": 
    print("Ronne") 
elif search == "information": 
    print("Yltehmufyel") 
elif search == "inspiration": 
    print("Ylgkyhufyel") 
elif search == "lawyer": 
    print("Nucioh") 
elif search == "no": 
    print("Le") 
elif search == "yes": 
    print("Iog") 
else: 
    print("No results were found for '" + search + "'") 

Answer 1

Sie können ein dict Objekt nur verwenden.

Beispiel:

words = {'ant': 'Ulf', 'back': 'Zuwp', 'ban' : 'Zul'} # etc 
try: 
    print(words[search]) 
except KeyError as e: 
    print("No results were found for '" + search + "'") 

Answer 2

ein dict Verwenden jeden Eingang mit dem entsprechenden Ausgang zu kartieren.

print("English to Exrian Dictionary") 
d = {"ant": "Ulf", 
    "back": "Zuwp", 
    # etc 
    } 

search = input("Enter the word you would like to translate: ").lower() 

if search in d: 
    print(d[search]) 
else: 
    print("No results were found for '" + search + "'") 

Answer 3

Dies könnte helfen:

def translate(item): 
try: 
    return { 
     'ant': "Ulf", 
     'back': "Zuwp", 
     'ban': "Zul" 
    }[item] 
except KeyError as e: 
    return "No results were found for '" + search + "'" 

print("English to Exrian Dictionary") 

search = raw_input("Enter the word you would like to translate: ").lower() 

print translate(search)