Wie finde ich findall oder suche nach Daten in Python?

Question

Hier ist meine Zeichenfolge,

str = 'A:[{type:"mb",id:9,name:"John",url:"/mb9/",cur:0,num:83498}, 
{type:"mb",id:92,name:"Mary",url:"/mb92/",cur:0,num:404}, 
{type:"mb",id:97,name:"Dan",url:"/mb97/",cur:0,num:139}, 
{type:"mb",id:268,name:"Jennifer",url:"/mb268/",cur:0,num:0}, 
{type:"mb",id:289,name:"Mike",url:"/mb289/",cur:0,num:0}],B: 
[{type:"mb",id:157,name:"Sue",url:"/mb157/",cur:0,num:35200}, 
{type:"mb",id:3,name:"Rob",url:"/mb3/",cur:0,num:103047}, 
{type:"mb",id:2,name:"Tracy",url:"/mb2/",cur:0,num:87946}, 
{type:"mb",id:26,name:"Jenny",url:"/mb26/",cur:0,num:74870}, 
{type:"mb",id:5,name:"Florence",url:"/mb5/",cur:0,num:37261}, 
{type:"mb",id:127,name:"Peter",url:"/mb127/",cur:0,num:63711}, 
{type:"mb",id:15,name:"Grace",url:"/mb15/",cur:0,num:63243}, 
{type:"mb",id:82,name:"Tony",url:"/mb82/",cur:0,num:6471}, 
{type:"mb",id:236,name:"Lisa",url:"/mb236/",cur:0,num:4883}]' 

I findall-Suche verwenden möchten alle Daten unter „name“ zu extrahieren und „url“ von str. Hier ist, was ich getan habe,

pattern = re.comile(r'type:(.*),id:(.*),name:(.*),url:(.*),cur:(.*),num: 
(.*)') 

for (v1, v2, v3, v4, v5, v6) in re.findall(pattern, str): 
    print v3 
    print v4 

Aber leider tut dies nicht, was ich will. Ist irgendwas falsch? Danke für Ihre Eingaben.

Answer 1

Sie sollten Sie nicht Zeichenfolge rufen "str", denn das ist eine integrierte Funktion. Aber hier ist eine Option für Sie:

# Find all of the entries 
x = re.findall('(?<![AB]:)(?<=:).*?(?=[,}])', s) 

['"mb"', '9', '"John"', '"/mb9/"', '0', '83498', '"mb"', '92', '"Mary"', 
'"/mb92/"', '0', '404', '"mb"', '97', '"Dan"', '"/mb97/"', '0', '139', 
'"mb"', '268', '"Jennifer"', '"/mb268/"', '0', '0', '"mb"', '289', '"Mike"', 
'"/mb289/"', '0', '0', '"mb"', '157', '"Sue"', '"/mb157/"', '0', '35200', 
'"mb"', '3', '"Rob"', '"/mb3/"', '0', '103047', '"mb"', '2', '"Tracy"', 
'"/mb2/"', '0', '87946', '"mb"', '26', '"Jenny"', '"/mb26/"', '0', '74870', 
'"mb"', '5', '"Florence"', '"/mb5/"', '0', '37261', '"mb"', '127', '"Peter"', 
'"/mb127/"', '0', '63711', '"mb"', '15', '"Grace"', '"/mb15/"', '0', '63243', 
'"mb"', '82', '"Tony"', '"/mb82/"', '0', '6471', '"mb"', '236', '"Lisa"', 
'"/mb236/"', '0', '4883'] 

# Break up into each section 
y = [] 
for i in range(0, len(x), 6): 
    y.append(x[i:i+6]) 

[['"mb"', '9', '"John"', '"/mb9/"', '0', '83498'] 
['"mb"', '92', '"Mary"', '"/mb92/"', '0', '404'] 
['"mb"', '97', '"Dan"', '"/mb97/"', '0', '139'] 
['"mb"', '268', '"Jennifer"', '"/mb268/"', '0', '0'] 
['"mb"', '289', '"Mike"', '"/mb289/"', '0', '0'] 
['"mb"', '157', '"Sue"', '"/mb157/"', '0', '35200'] 
['"mb"', '3', '"Rob"', '"/mb3/"', '0', '103047'] 
['"mb"', '2', '"Tracy"', '"/mb2/"', '0', '87946'] 
['"mb"', '26', '"Jenny"', '"/mb26/"', '0', '74870'] 
['"mb"', '5', '"Florence"', '"/mb5/"', '0', '37261'] 
['"mb"', '127', '"Peter"', '"/mb127/"', '0', '63711'] 
['"mb"', '15', '"Grace"', '"/mb15/"', '0', '63243'] 
['"mb"', '82', '"Tony"', '"/mb82/"', '0', '6471'] 
['"mb"', '236', '"Lisa"', '"/mb236/"', '0', '4883']] 

# Name is 3rd value in each list and url is 4th 
for i in y: 
    name = i[2] 
    url = i[3] 

Answer 2

Sie können dies versuchen:

import re 
data = """ 
A:[{type:"mb",id:9,name:"John",url:"/mb9/",cur:0,num:83498}, 
{type:"mb",id:92,name:"Mary",url:"/mb92/",cur:0,num:404}, 
{type:"mb",id:97,name:"Dan",url:"/mb97/",cur:0,num:139}, 
{type:"mb",id:268,name:"Jennifer",url:"/mb268/",cur:0,num:0}, 
{type:"mb",id:289,name:"Mike",url:"/mb289/",cur:0,num:0}],B: 
[{type:"mb",id:157,name:"Sue",url:"/mb157/",cur:0,num:35200}, 
{type:"mb",id:3,name:"Rob",url:"/mb3/",cur:0,num:103047}, 
{type:"mb",id:2,name:"Tracy",url:"/mb2/",cur:0,num:87946}, 
{type:"mb",id:26,name:"Jenny",url:"/mb26/",cur:0,num:74870}, 
{type:"mb",id:5,name:"Florence",url:"/mb5/",cur:0,num:37261}, 
{type:"mb",id:127,name:"Peter",url:"/mb127/",cur:0,num:63711}, 
{type:"mb",id:15,name:"Grace",url:"/mb15/",cur:0,num:63243}, 
{type:"mb",id:82,name:"Tony",url:"/mb82/",cur:0,num:6471}, 
{type:"mb",id:236,name:"Lisa",url:"/mb236/",cur:0,num:4883}] 
""" 
full_data = [i[1:-1] for i in re.findall('(?<=name:)".*?"(?=,)|(?<=url:)".*?"(?=,)', data)] 
final_data = [full_data[i]+":"+full_data[i+1] for i in range(0, len(full_data)-1, 2)] 
print(full_data) 

Ausgabe

['John:/mb9/', 'Mary:/mb92/', 'Dan:/mb97/', 'Jennifer:/mb268/', 'Mike:/mb289/', 'Sue:/mb157/', 'Rob:/mb3/', 'Tracy:/mb2/', 'Jenny:/mb26/', 'Florence:/mb5/', 'Peter:/mb127/', 'Grace:/mb15/', 'Tony:/mb82/', 'Lisa:/mb236/']