Was das richtige Format von y3 Signal ist

Question

ich den folgenden Code geschrieben habe:

freq=[261.626, 277.183, 293.665, 311.127, 329.628, 349.228, 369.994, 391.995,... 
    415.305, 440.000, 466.164, 493.883, 523.251, 554.365,... 
    587.330, 622.254, 659.255, 698.456, 739.989, 783.991, 830.609, 880.000,... 
    932.328, 987.767]; 
freq_length=length(freq); 

notes=['C4 ';'C#4';'D4 ';'D#4';'E4 ';'F4 ';'F#4';'G4 ';'G#4';'A4 ';'A#4';... 
    'B4 ';'C5 ';'C#5';'D5 ';'D#5';'E5 ';'F5 ';'F#5';'G5 ';'G#5';'A5 ';'A#5';'B5 ']; 
notes_length=length(notes); 

Duration=[1,1/2,1/4,1/8,1/16,1/32,1/64]; 
DurationLength=length(Duration); 
DurationName=['whole Note','halfNote','QuarterNote','EighthNote','SixteenthNote',... 
'ThirtySecondNote','SixtyFourNote']; 

increases=[0,1/2,3/4,9/8]; 
IncreasesLength=length(increases); 
increasesName=['ZeroDots','OneDot','TwoDots','ThreeDots']; 

%endeiktikh timh sampleRate 
SampleRate=1/20000; 

%typikh timh (se sec gia thn whole note) 
TimeValue=1.6; 

TimeNotesSize=int64(IncreasesLength)*int64(DurationLength); 
TimeNotes=zeros(TimeNotesSize,1); 

%Ypologismos TimeValue gia kathe Duration,increases 
for i=1:DurationLength 
    for j=1:IncreasesLength 
     TimeNotes(j+IncreasesLength*(i-1))=Duration(i)*(1+increases(j))*TimeValue; 
     %disp(j+IncreasesLength*(i-1)); 
    end 
end 

for i = 1:TimeNotesSize 
    soundVector = zeros(notes_length,TimeNotesSize,int64(TimeNotes(i)/SampleRate)); 
end 

for i = 1:1:notes_length % for every note 
    for j=1:TimeNotesSize %for every note duration 
     for k=0:SampleRate:TimeNotes(j) %for the SampleRate space 
      soundVector(i,j,int64(k/SampleRate)+1)=sin(2*pi*freq(i)*k); 
     end 
    end 
end 

%spectogram 
y1=sin(2*pi*freq(1)*(0:SampleRate:TimeValue)); 
y2=sin(2*pi*freq(1)*(0:SampleRate:TimeNotes(1))); 
y3=soundVector(1,1,:); 
window=hamming(512); 
noverlap=256; 
nfft=1024; 
[S,F,T,P]=spectrogram(y3,window,noverlap,nfft,Fs,'yaxis'); 
surf(T,F,10*log10(P),'edgecolor','none'); 
axis tight; 
view(0,90); 
set(gca,'clim',[-80,-30]); 
xlabel('Time (seconds)'); 
ylabel('Frequency (Hz)'); 

Das Hauptziel eine Musik Lied gegeben, die Pentagramm Noten dieses Lied drucken. Ich kann die Signale y1 und y2 drucken, aber nicht die von y3. Die Signale y3 und y2 müssen übereinstimmen.

Der Fehler, dass Konsole kehrt ist:

Error using welchparse>segment_info (line 188) 
The length of the segments cannot be greater than the length of the input signal. 

Error in welchparse (line 32) 
[L,noverlap,win] = segment_info(M,win,noverlap); 

Error in spectrogram (line 172) 
[x,nx,~,~,~,win,~,~,noverlap,~,~,options] = welchparse(x,esttype,varargin{:}); 

Error in play_notes (line 57) 
[S,F,T,P]=spectrogram(y3,window,noverlap,nfft,Fs,'yaxis'); 

Was isis es, dass ich falsch mache?

Erster Fehler:>[S,F,T,P]=spectrogram(y2,window,noverlap,nfft,1/SampleRate,'yaxis'); statt [S,F,T,P]=spectrogram(y3,window,noverlap,nfft,Fs,'yaxis');

Zweiter Fehler: y3=soundVector(1,1,1:int64(TimeNotes(1)/SampleRate)); statt y3=soundVector(1,1,:);

Answer 1

Ich weiß nicht, warum (:, :) ist necessery aber [S,F,T,P]=spectrogram(y3(:,:),window,noverlap,nfft,1/SampleRate,'yaxis'); funktioniert!