Python Merge-Funktion in Matlab nicht übersetzt

Question

Für die Arbeit folgende schön arbeiten Python-Code

#-------------------------------------------------- 
s = [[1,2,3],[3,6],[9,0],[0,8]] 
s = [set(i) for i in s if i] 
t = [] 
while len(t) != len(s): 
    t = s 
    s = [] 
    for i in range(len(t)): 
     for j in range(len(s)): 
      if not s[j].isdisjoint(t[i]): 
       s[j] = s[j].union(t[i]) 
       break 
     else: s.append(t[i]) 
print(s) 
#-------------------------------------------------- 
>>> [{1, 2, 3, 6}, {0, 9, 8}] 
#-------------------------------------------------- 

Meine Übersetzung Matlab als:

%-------------------------------------------------- 
s = {[1,2,3],[3,6],[9,0],[0,8]}; 
t = {}; 
while length(t) ~= length(s) 
    t = s; 
    s = {}; 
    for i=1:length(t) 
     for j=1:length(s) 
      if ~isempty(intersect(s{j},t{i})) 
       s{j} = union(s{j},t{i}); 
       break 
      else 
       s = [s; t{i}]; 
      end 
     end 
     if isempty(s); s = [s; t{i}]; end 
    end 
end 
s{:} 
%-------------------------------------------------- 
ans = 
    1  2  3  6 
ans = 
    0  8  9 
ans = 
    0  8 
%-------------------------------------------------- 

Werke falsch!

Der Q: Was verursacht das?

Refs: Python: simple list merging based on intersections
Python Code nach agf

Answer 1

Nun, ich eine Lösung finden könnte wie folgt aussehen.

%-------------------------------------------------- 
s = {[1,2,3],[3,6],[9,0],[0,8]}; 
t = {}; 
while length(t) ~= length(s) 
    t = s; 
    s = {}; 
    for i=1:length(t) 
     for j=1:length(s) 
      if ~isempty(intersect(s{j},t{i})) 
       s{j} = union(s{j},t{i}); 
       j = 0; 
       break; 
      end 
     end 
     if isempty(s) || (j == length(s)); 
      s = [s; t{i}]; 
     end 
    end 
end 
s{:} 
%-------------------------------------------------- 
ans = 
    1  2  3  6 
ans = 
    0  8  9 

wo j = 0; und if isempty(s) || (j == length(s));else: wie in der Python-Version erfüllen.