Checkbox Überprüfte Probleme in win32 api C++

Question

Ich habe diesen Code in C++ gemacht und ich möchte fragen, warum, wenn ich eine CheckBox drücke alle Status ändern. Beispiel:

CB1 = aktiviert CB2 = UnChecked

CB1 = Press

CB1 = UnChecked CB2 = aktiviert

möchte ich nur Arbeit einer von ihnen machen, nicht die beiden an die selbe Zeit.

Hier haben Sie den Code:

LRESULT CALLBACK WndProc(HWND hwnd, UINT msg, WPARAM wParam, LPARAM lParam) 
{ 

    switch (msg) 
    { 
    case WM_CREATE: 
    { 

     //Load the background image 
     HWND hWndBackground; 
     HANDLE hBitmap; 
     hBitmap = LoadImage(NULL, TEXT("\header.bmp"), IMAGE_BITMAP, 0, 0, LR_LOADFROMFILE); 
     if (hBitmap != NULL) 
     { 
      hWndBackground = CreateWindow(TEXT("STATIC"), TEXT("image box"), 
       WS_CHILD | WS_VISIBLE | SS_BITMAP, 
       0, 0, 470, 130, 
       hwnd, (HMENU)2000, NULL, NULL); 
      SendMessage(hWndBackground, STM_SETIMAGE, IMAGE_BITMAP, LPARAM(hBitmap)); 
     } 

     //Load CheckBox1 
     CreateWindow(TEXT("button"), TEXT("Show Title"), 
      WS_VISIBLE | WS_CHILD | BS_CHECKBOX, 
      25, 220, 114, 45, 
      hwnd, (HMENU)1, ((LPCREATESTRUCT)lParam)->hInstance, NULL); 
     CheckDlgButton(hwnd, 1, BST_CHECKED); 

     //Load Textbox1 
     CreateWindowEx(WS_EX_CLIENTEDGE, TEXT("Edit"), TEXT("140"), 
      WS_CHILD | WS_VISIBLE, 
      115, 230, 50, 25, 
      hwnd, NULL, NULL, NULL); 

     //Load Label1 
     CreateWindowW(L"Static", L"0", 
      WS_CHILD | WS_VISIBLE, 0, 0, 10, 30, hwnd, (HMENU)1, NULL, NULL); 

     //Load CheckBox2 
     CreateWindow(TEXT("button"), TEXT("Show Title1"), 
      WS_VISIBLE | WS_CHILD | BS_CHECKBOX, 
      25, 250, 114, 45, 
      hwnd, (HMENU)2, ((LPCREATESTRUCT)lParam)->hInstance, NULL); 
     CheckDlgButton(hwnd, 2, BST_UNCHECKED); 

     break; 
    } 

    case WM_COMMAND: 
    { 
     BOOL checked = IsDlgButtonChecked(hwnd, 1); 
     if (checked) { 
      CheckDlgButton(hwnd, 1, BST_UNCHECKED); //SetWindowText(hwnd, title or TEXT("algo"); 

     } 
     else { 
      CheckDlgButton(hwnd, 1, BST_CHECKED); 
      //action("chatlim", 150, 0, 0); 
     } 

     BOOL checked1 = IsDlgButtonChecked(hwnd, 2); 
     if (checked1) { 
      CheckDlgButton(hwnd, 2, BST_UNCHECKED); 
     } 
     else { 
      CheckDlgButton(hwnd, 2, BST_CHECKED); 
     } 
     break; 
    } 

    case WM_DESTROY: 
    { 
     PostQuitMessage(0); 
     break; 
    } 
    } 
    return DefWindowProc(hwnd, msg, wParam, lParam); 
} 

Answer 1

behoben, müssen Sie einfach Schalter und Fall verwenden.