Join 2 Arrays von Schlüssel und Wert (AngularJS)

Question

Ich habe 2 Objekte

{ 
    "_id": "58b7f36b3354c24630f6f3b0", 
    "name": "refcode", 
    "caption": "Reference", 
    "type": "string", 
    "search": false, 
    "required": false, 
    "table": true, 
    "expansion": true 
}, 

und

{ 
    "_id": "58b7f36b3354c24630f6f3c8", 
    "vacancyid": "0", 
    "refcode": "THIS IS MY REF", 
    "position": "Test", 
    "jobtype": "Temp", 
    "department": "Industrial", 
    "branch": "Office", 
    "startdate": "02/12/2013", 
    "contactname": "Person Name", 
    "contactemail": "person@domain", 
    "Q_V_TYP": "Daily", 
    "score": 0 
}, 

Objekt definiert man, was für ein Feld sein sollte und was es

Die aufgerufen wird zweites Objekt ist eine Stellenbeschreibung.

Was ich brauche, ist ein Feld zu jedem Schlüssel übereinstimmen (dies auch klingt verwirrend ich meinen Kopf, so ist hier ein Beispiel)

{ 
    "_id": "58b7f36b3354c24630f6f3c8", 
    "vacancyid": "0", 
    "refcode": { 
    "_id": "58b7f36b3354c24630f6f3b0", 
    "name": "refcode", 
    "caption": "Reference", 
    "type": "string", 
    "search": false, 
    "required": false, 
    "table": true, 
    "expansion": true, 
    "value": "THIS IS MY REF" 
    } 
    },  
    "position": "Test", 
    "jobtype": "Temp", 
    "department": "Industrial", 
    "branch": "Office", 
    "startdate": "02/12/2013", 
    "contactname": "Person Name", 
    "contactemail": "person@domain", 
    "Q_V_TYP": "Daily", 
    "score": 0 
}, 

Answer 1

Hier gehen Sie:

var def = { 
 
    "_id": "58b7f36b3354c24630f6f3b0", 
 
    "name": "refcode", 
 
    "caption": "Reference", 
 
    "type": "string", 
 
    "search": false, 
 
    "required": false, 
 
    "table": true, 
 
    "expansion": true 
 
}; 
 

 
var jobDesc = { 
 
    "_id": "58b7f36b3354c24630f6f3c8", 
 
    "vacancyid": "0", 
 
    "refcode": "THIS IS MY REF", 
 
    "position": "Test", 
 
    "jobtype": "Temp", 
 
    "department": "Industrial", 
 
    "branch": "Office", 
 
    "startdate": "02/12/2013", 
 
    "contactname": "Person Name", 
 
    "contactemail": "person@domain", 
 
    "Q_V_TYP": "Daily", 
 
    "score": 0 
 
}; 
 

 
var jobDescKeysArr = Object.keys(jobDesc); 
 

 
if (jobDescKeysArr.indexOf(def.name) !== -1) { 
 
    // A match. 
 
    def.value = jobDesc[def.name]; 
 

 
    jobDesc[def.name] = Object.assign({}, def); 
 

 
    console.log(jobDesc) 
 
}