SQL-Abfrage: Wie doppelte Servicegebühr zu entfernen?

Question

Ich habe diese drei Tisch

ITEM Tabelle:

ITEM_ID AMOUNT_DUE SERVICE_CHARGE 
----------------------------------- 
1   1000  100 

TENDER Tabelle:

ITEM_ID TYPE_ID AMOUNT 
------------------------------- 
1   0  600 
1   1  500 

TYPE Tabelle:

TYPE_ID TYPE_NAME 
------------------------------- 
0   CASH 
1   CREDIT 

Ich habe versucht:

select 
    TYPE_NAME, 
    sum(AMOUNT) as Amount, 
    sum(ServiceCharge) as SC 
from 
    TENDER 
left join 
    TYPE on TYPE.TYPE_ID = TENDER.TYPE_ID 
left join 
    ITEM on ITEM.ITEM_ID = TENDER.ITEM_ID 
group by 
    TYPE_NAME 

Aber Ergebnisse für Service Charge wie

TYPE_NAME AMOUNT SC 
------------------------------- 
CASH   650  100 
CREDIT  500  100 

HINWEIS dupliziert wurden: Service Charge * berechnet wird 10

Answer 1

vielleicht so etwas wie folgt aus:

select TYPE_NAME, sum(AMOUNT) as Amount, 
sum(ServiceCharge)/ (COUNT(*) OVER (PARTITION BY TENDER.ITEM_ID)) as SC 
from TENDER 
LEFT JOIN TYPE ON TYPE.TYPE_ID = TENDER.TYPE_ID 
LEFT JOIN ITEM ON ITEM.ITEM_ID = TENDER.ITEM_ID 
GROUP BY TYPE_NAME, TENDER.ITEM_ID; 

Answer 2

Ich vermute, dass Sie dies wünschen:

select ITEM.ITEM_ID, ServiceCharge, 
     SUM(CASE WHEN TYPE_NAME = 'CASH' THEN Amount END) as Cash, 
     SUM(CASE WHEN TYPE_NAME = 'CREDIT' THEN Amount END) as Credit 
from TENDER LEFT JOIN 
    TYPE 
    ON TYPE.TYPE_ID = TENDER.TYPE_ID LEFT JOIN 
    ITEM 
    ON ITEM.ITEM_ID = TENDER.ITEM_ID 
GROUP BY ITEM.ITEM_ID, ServiceCharge; 

Dies setzt die Werte in Spalten, so t hier ist keine Vervielfältigung.

Answer 3

Da die service charge 10% des amount ist, brauchen Sie nicht wirklich zu join zum item Tisch. Stattdessen vermehren nur die sum(amount) von 0,1:

select TYPE_NAME, sum(AMOUNT) as Amount, sum(AMOUNT) * .1 as SC 
from TENDER 
    LEFT JOIN TYPE ON TYPE.TYPE_ID = TENDER.TYPE_ID 
GROUP BY TYPE_NAME 

• SQL Fiddle Demo

---

in Resultierende:

type_name Amount SC 
Cash  600  60 
Credit  500  50 

Answer 4

Wird diese Arbeit für Sie. Bitte ändern Sie die Spaltennamen nach Ihren

SELECT 
    tender.item,typename,SUM(amount)as amount, SUM(Service_Charge/cntItem) as servercharge 
FROM 
    woddb.TENDER_Table as Tender 
INNER JOIN 
    (SELECT item, count(item) as cntItem FROM woddb.Tender_Table GROUP BY ITEM) as cntTable 
ON 
    Tender.item = cntTable.Item 
LEFT JOIN 
    woddb.TYPE_Table as TYPETable 
ON 
    TYPETable.TYPEID = Tender.TYPEID 
LEFT JOIN 
    woddb.ITEM_table as ITEMtable 
ON 
    ITEMtable.ITEM = Tender.ITEM 
GROUP BY 
    tender.item,typename 

Answer 5

I kombiniert Slava Murygin und sandeep rawat Antworten, diese geben mir richtige Ergebnisse für nachfolgende Umsatz.

kamen mit diesem

;WITH SUMS AS (
select TYPE_NAME, AMOUNT as Amount, 
sum(ServiceCharge)/ (COUNT(*) OVER (PARTITION BY TENDER.ITEM_ID)) as SC 
from TENDER 
LEFT JOIN TYPE ON TYPE.TYPE_ID = TENDER.TYPE_ID 
LEFT JOIN ITEM ON ITEM.ITEM_ID = TENDER.ITEM_ID 
GROUP BY TYPE_NAME, TENDER.ITEM_ID, AMOUNT 
) 
Select Type_Name , Amount, Tender.ITEM_ID 
From Sums 
Group by TYPE_NAME 

Dank up!