Oracle PL/SQL durch neue Linie geteilt

Question

Wie String geteilt durch neue Zeile oder andere char String

ABC|123 
xyz|098 

---

Um

ABC --- 123 
xyz --- 098 

Answer 1

Make Orakel split Funktion, die varray zurückzukehren. Hier ist V_ARRAY

1. erstellen TYPE V_ARRAY
2. geben danach split Funktion erstellen, die Rückkehr V_ARRAY

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CREATE OR REPLACE TYPE V_ARRAY AS VARRAY(1000) OF VARCHAR2(4000); 

CREATE or REPLACE function split(str varchar2, patt varchar2) 
RETURN v_array as 
    s BINARY_integer; 
    e BINARY_integer; 
    i BINARY_integer; 
    token v_array; 
begin 
    token := v_array(); 
    i :=1; 
    s := 0; 
    e := INSTR(str, patt); 
    while(e > 0) loop 
     token.extend; // add new varchar2 
     token(i) := substr(str, s+1, e-s-1); 
     s := e; 
     e := INSTR(str, patt, s+1); 
     i := i + 1; 
    end loop; 
    token.extend; 
    token(i) := substr(str, s+1, length(str) -1); 
    return token; 
end; 

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---

E xample

declare 
    str varchar(10000); 
    line varchar(10000); 
    lines v_array; 
    subs v_array; 
begin 
    str := 'ABCe123';--|| chr(10) ||'xyz|098'; 
    lines := split(str, chr(10)); 
    --DBMS_OUTPUT.PUT_LINE(lines.count); 
    for i in 1.. lines.count loop 
    line := lines(i); 
    -- DBMS_OUTPUT.PUT_LINE('line :' || line); 
    subs := split(line, '|'); 
    -- DBMS_OUTPUT.PUT_LINE(subs.count); 
    DBMS_OUTPUT.PUT_LINE(subs(1) || '---' || subs(1)); 
    end loop;  
end; 

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ref: A function to split, loop through

Answer 2

Versuchen regexp_substr Funktion ...

select regexp_substr('ABC|123','[^|]+',1,1) part1, regexp_substr('ABC|123','[^|]+',1,2) part2 from dual

Und bei neue Linie (CR/LF) es aussehen würde, so:

`regexp_substr(mystr,'[^('||chr(13)||chr(10)||')]+',1,1) part1, 
    regexp_substr(mystr,'[^('||chr(13)||chr(10)||')]+',1,2) part2`