Python3 Codefehler, während die Bilder

Question

Hier ist das Herunterladen der Code, den ich Bilder von den Google Bildern zum Download verwenden .:

def get_soup(url, header): 
    return BeautifulSoup(urllib.request.urlopen(urllib.request.Request(url, headers=header)), 'html.parser') 


def get_images_for_term(text, width, height, number_of_images=3): 
    search_keywords = '' 
    collect_valid_urls = [] 
    query = text 
    if not (height and width) == '1': 
     keyword_keys = ' high quality background imagesize:' + width + 'x' + height 
    else: 
     keyword_keys = ' high quality background' 
    query = query + keyword_keys 
    max_images = number_of_images 

    try: 
     if not ((height == width) and (height and width) == '1'): 
      search_keywords = text + '_' + height + 'by' + width 

     else: 
      search_keywords = text 
     os.makedirs(search_keywords) 
    except OSError as e: 
     if e.errno != 17: 
      raise 
     pass 

    query = query.split() 
    query = '+'.join(query) 
    url = "google Url" 

    header = {'User-Agent': "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) " 
          "Chrome/43.0.2357.134 Safari/537.36"} 
    soup = get_soup(url, header) 
    ActualImages = [] 
    for a in soup.find_all("div", {"class": "rg_meta"}): 
     link = json.loads(a.text)["ou"] 

     ActualImages.append(link) 

    Stop_Counter = 0 
    for i, img in enumerate(ActualImages): 

     try: 
      print(img) 
      req = urllib.request.Request(img, headers={'User-Agent': header}) 
      raw_img = urllib.request.urlopen(req, None, 15).read() 

      print(raw_img[0]) 
      if raw_img[0] != '<': 
       image = np.asarray(bytearray(raw_img), dtype="uint8") 
       image = cv2.imdecode(image, cv2.IMREAD_COLOR) 
       try: 
        blur_map, score, blurry = estimate_blur(image) 
       except IOError and AttributeError: 
        blurry = False 
       if not blurry: 
        collect_valid_urls.append(img) 
        Output_file = open(search_keywords + "/" + str(Stop_Counter + 1) + ".jpg", 'wb') 

        Output_file.write(raw_img) 
        Output_file.close() 
        Stop_Counter += 1 
        if Stop_Counter == max_images: 
         print("Done with downloading the images") 
         break 
       else: 
        print("Image is Blurry.") 

     except Exception as e: 
      print("could not load : " + img) 

      print(e) 


get_images_for_term('cats', '200', '300') 

ich die folgende Fehlermeldung erhalten:

https://i.pinimg.com/736x/ec/65/86/ec658681dada104797b3f1f49026c7f1--cat-wallpaper-iphone-wallpaper.jpg 
could not load : https://i.pinimg.com/736x/ec/65/86/ec658681dada104797b3f1f49026c7f1--cat-wallpaper-iphone-wallpaper.jpg 
expected string or bytes-like object 

Bitte, hilf mir, den Code zu verbessern, damit er mir keine Fehler mehr gibt.

 
raw_img = urllib.request.urlopen(img, timeout=15).read() 

oder reparieren die Anfrage objet, ohne headers für den vorherigen Header in einem neuen Wörterbuch erklärt:

Answer 1

urlopen einen String URL als Parameter akzeptiert, sollten Sie Ihren Link direkt zu übergeben

 
req = urllib.request.Request(img, headers=header) 
raw_img = urllib.request.urlopen(req, None, 15).read()