mySql Abfragegruppe nach Datum nach mit, um nicht arbeiten

Question

Ich habe zwei Tabellen wie diese und ich möchte neuesten Daten nach Datum

tbl_fruit_info 
+-----+--------+ 
| sId | sName | 
+-----+--------+ 
| 1 | Apple | 
| 2 | Banana | 
| 3 | Orange | 
+-----+--------+ 

tbl_fruit_data 
+------------+----------+-------------+ 
| date | fruit_id | fruit_price | 
+------------+----------+-------------+ 
| 2017-01-26 |  1 | 44.7  | 
| 2017-01-27 |  1 | 51   | 
| 2017-01-25 |  1 | 71.5  | 
| 2017-01-21 |  2 | 44   | 
| 2017-01-23 |  2 | 55   | 
| 2017-01-24 |  2 | 71   | 
+------------+----------+-------------+ 

ich mit diesem

versucht

    SELECT tbl_fruit_info.*, tbl_fruit_data.* 
        FROM tbl_fruit_data 
        LEFT JOIN 
         tbl_fruit_info ON tbl_fruit_info.sId = tbl_fruit_data.fruit_id 
        GROUP BY 
         tbl_fruit_info.sId 
        ORDER BY 
         max(tbl_fruit_data.date) DESC; 

Der Output Suche für ist wie folgt:

+-----+--------+----------------------------+ 
| sId | sName | date   |fruit_price | 
+-----+--------+----------------------------+ 
| 1 | Apple | 2017-01-27 | 51   | 
| 2 | Banana | 2017-01-24 | 71   | 
| 3 | Orange | 0000-00-00 | 0   | 
+-----+--------+----------------------------+ 

Aber ich bekomme diese:

+-----+--------+----------------------------+ 
| sId | sName | date   |fruit_price | 
+-----+--------+----------------------------+ 
| 1 | Apple | 2017-01-26 | 44.7  | 
| 2 | Banana | 2017-01-21 | 44   | 
+-----+--------+----------------------------+ 

Jede Hilfe würde sehr geschätzt werden.

Answer 1

select * from tbl_fruit_data f 
    left join tbl_fruit_info i ON i.sId = f.fruit_id 
where f.Date = 
    (Select max(date) from tbl_fruit_data 
    where fruit_id = f.fruit_id) 

Answer 2

SELECT fi.*, fd.* 
FROM tbl_fruit_data fd 
    FULL OUTER JOIN tbl_fruit_info fi ON fi.sId = fd.fruit_id 
WHERE fd.fruit_id IS NULL OR fd.date = (
    SELECT max(fd_inner.date) 
    FROM tbl_fruit_data fd_inner 
    WHERE fd_inner.fruit_id = fd.fruit_id 
) 
ORDER BY fd.date DESC; 

-Update 2017.01.30: Enthält Reihen in tbl_fruit_info, die jetzt keine entsprechende Zeile in tbl_fruit_data haben.

Answer 3

create table #t1 
(id int,name varchar(100)); 


create table #t2(
[date] date, 
id int, 
price float) 

insert into #t1 
select 1,'Apple' 
union 
select 2,'Banana' 

insert into #t2 
select getdate()-3,1,33.2 
union 
select getdate()-2,1,30.5 
union 
select getdate()-4,1,23.4 
union 
select getdate()-3,2,21 
union 
select getdate()-2,2,35 

Abfrage

select q.name,t2.* from (
select t1.id,t1.name,MAX(t2.date) as date from #t1 t1 
inner join #t2 t2 on t1.id=t2.id 
group by t1.id,t1.name 
) as q inner join #t2 t2 
on q.id=t2.id and t2.date=q.date 

Edit: Feste, ersetzt CTE mit subquery dank dadde für CTE unter Hinweis darauf, nicht in MySQL unterstützt. CTE oder Unterabfrage macht den gleichen Job hier

Answer 4

Ok hier geht.

** Holen Sie sich die neueste Preise für Obst, mit Zusatz von Früchten keinen Preis mit

SELECT d1.date, d1.fruit_id, d1.fruit_price, i.sId, i.sName 
FROM tbl_fruit_info i 
LEFT JOIN tbl_fruit_data d1 
ON d1.fruit_id = i.sId 
WHERE d1.date = (SELECT MAX(d2.date) 
       FROM tbl_fruit_data d2 
       WHERE d2.fruit_id = d1.fruit_id 
       ) 
UNION 
SELECT CAST('0001-01-01' AS datetime) date, i.sId fruit_id, 0 fruit_price, i.sId, i.sName 
FROM tbl_fruit_info i 
WHERE i.sId NOT IN (SELECT d2.fruit_id FROM tbl_fruit_data d2) 

Sql Geige für den Test auf der gleichen Daten zur Verfügung stellt in Frage:

http://sqlfiddle.com/#!9/872ed4/9

Verwendete diese Definitionen

CREATE TABLE tbl_fruit_info 
    (`sId` int, `sName` varchar(6)) 
; 

INSERT INTO tbl_fruit_info 
    (`sId`, `sName`) 
VALUES 
    (1, 'Apple'), 
    (2, 'Banana'), 
    (3, 'Orange') 
; 


CREATE TABLE tbl_fruit_data 
    (`date` datetime, `fruit_id` int, `fruit_price` int) 
; 

INSERT INTO tbl_fruit_data 
    (`date`, `fruit_id`, `fruit_price`) 
VALUES 
    ('2017-01-26 00:00:00', 1, 44.7), 
    ('2017-01-27 00:00:00', 1, 51), 
    ('2017-01-25 00:00:00', 1, 71.5), 
    ('2017-01-21 00:00:00', 2, 44), 
    ('2017-01-23 00:00:00', 2, 55), 
    ('2017-01-24 00:00:00', 2, 71) 
; 

Answer 5

Mit dadde Geige (mit einigen Tweaks) - und unter der Annahme, dass der MySQL-Tag korrekt ist ...

CREATE TABLE tbl_fruit_info 
    (`sId` int auto_increment PRIMARY KEY, `sName` varchar(6)) 
; 

INSERT INTO tbl_fruit_info 
    (`sId`, `sName`) 
VALUES 
    (1, 'Apple'), 
    (2, 'Banana'), 
    (3, 'Orange') 
; 


CREATE TABLE tbl_fruit_data 
    (`date` datetime, `fruit_id` int, `fruit_price` int, primary key (fruit_id,date)) 
; 

INSERT INTO tbl_fruit_data 
    (`date`, `fruit_id`, `fruit_price`) 
VALUES 
    ('2017-01-26 00:00:00', 1, 44.7), 
    ('2017-01-27 00:00:00', 1, 51), 
    ('2017-01-25 00:00:00', 1, 71.5), 
    ('2017-01-21 00:00:00', 2, 44), 
    ('2017-01-23 00:00:00', 2, 55), 
    ('2017-01-24 00:00:00', 2, 71) 
; 

SELECT a.sid 
    , a.sname 
    , COALESCE(b.date,'0000-00-00') date 
    , COALESCE(b.fruit_price,0) fruit_price 
    FROM tbl_fruit_info a 
    LEFT 
    JOIN 
    (SELECT x.* 
     FROM tbl_fruit_data x 
     JOIN 
      (SELECT fruit_id, MAX(date) date 
     FROM tbl_fruit_data 
     GROUP 
      BY fruit_id 
    ) y 
    ON y.fruit_id = x.fruit_id 
    AND y.date = x.date) b 
    ON b.fruit_id = a.sid; 
+-----+--------+---------------------+-------------+ 
| sid | sname | date    | fruit_price | 
+-----+--------+---------------------+-------------+ 
| 1 | Apple | 2017-01-27 00:00:00 |   51 | 
| 2 | Banana | 2017-01-24 00:00:00 |   71 | 
| 3 | Orange | 0000-00-00   |   0 | 
+-----+--------+---------------------+-------------+