Question

Im Versuch, eine einfache UPDATE Abfrage auszuführen:

UPDATE students SET enterTime = '".$enterTime."' WHERE s_id = '".$s_id."'; UPDATE timeLimit SET listed = listed + 1 WHERE enterTime = '".$enterTime."' AND building = '".$building."';" 

Es funktioniert gut in MySQL-Version 5.1, mein Server MySQL-Version 5.7 aktualisiert wurde, und ich erhalte die folgenden Fehler:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'UPDATE students SET enterTime = '09:00' WHERE ' at line 1 BEGIN; UPDATE students SET enterTime = '09:00' WHERE s_id = '312433931' ; UPDATE timeLimit SET listed = listed + 1 WHERE enterTime = '09:00' AND building = '2'; UPDATE timeLimit SET listed = listed - 1 WHERE enterTime = '08:00' AND building = '2'; COMMIT;

PHP-Code:

function update_time_for_student($student,$enterTime,$oldTime){ 
    $s_id = $student['s_id']; 
    $building = $student['building']; 
    $query = "BEGIN; UPDATE students 
       SET enterTime = '".$enterTime."' 
       WHERE s_id = '".$s_id."' ;    
       UPDATE timeLimit 
       SET listed = listed + 1 
       WHERE enterTime = '".$enterTime."' AND building = '".$building."'; 
       UPDATE timeLimit 
       SET listed = listed - 1 
       WHERE enterTime = '".$oldTime."' AND building = '".$building."'; COMMIT;"; 
    if (mysql_query($query)){ 
     $fullName = $student['fname']." ".$student['lname']; 
     send_email($student['email'],$enterTime,$fullName,$s_id); 
     header("Location:/index.php?d=1"); 
    } else { 
     echo mysql_error(); 
     echo "<br/>"; 
     echo $query; 
     //header("Location:/index.php?d=3"); 
    } 
} 

Vielen Dank für Ihre Hilfe!

Answer 1

Option-1

Versuchen Sie, die Linien in mehrere PHP-Anweisungen zu brechen:

$query = "BEGIN"; 
mysql_query($query) or die (mysql_error()); 

$query = "UPDATE students SET enterTime = '".$enterTime."' WHERE s_id = '".$s_id."';"; 
mysql_query($query) or die (mysql_error()); 

$query = "UPDATE timeLimit SET listed = listed + 1 WHERE enterTime = '".$enterTime."' AND building = '".$building."';"; 
mysql_query($query) or die (mysql_error()); 

$query = "COMMIT"; 
mysql_query($query) or die (mysql_error()); 

Option-2

Sie brauchen multi_query stattdessen zu verwenden. Dokumente here

Hinweis: mysql_ * Befehle sind veraltet und in PhP7 entfernt. Verwenden Sie stattdessen mysqli oder PDO. Siehe die akzeptierte Antwort here