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Ich habe ein Formular mit Datei-Upload. Ich möchte zu zwei Aufgaben durchführen: Eins ist Daten an die Datenbank senden und Datei hochladen durch Ajax und nach Ajax erfolgreich wird ein anderes Formular bilden action.ajax funktionieren ordnungsgemäß, aber nach Ajax erfolgreich Formular Aktion funktioniert nicht Bitte helfenFormular Aktion funktioniert nicht nach Ajax erfolgreich
main.php
<!doctype html>
<html>
<head>
<!-- Latest compiled and minified CSS -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">
<!-- Optional theme -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap-theme.min.css" integrity="sha384-rHyoN1iRsVXV4nD0JutlnGaslCJuC7uwjduW9SVrLvRYooPp2bWYgmgJQIXwl/Sp" crossorigin="anonymous">
<!-- Latest compiled and minified JavaScript -->
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js" integrity="sha384-Tc5IQib027qvyjSMfHjOMaLkfuWVxZxUPnCJA7l2mCWNIpG9mGCD8wGNIcPD7Txa" crossorigin="anonymous"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<script type="text/javascript">
function mycall() {
//disable the default form submission
event.preventDefault();
//grab all form data
var formData = new FormData(document.getElementById('data'));
$.ajax({
url: 'addToMySQL.php',
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (returndata) {
alert(returndata);
}
});
return false;
}
</script>
</head>
<body>
<form method='post' enctype="multipart/form-data" id="data" action="try.php" >
<div class="form-input">
<label for="exampleSelect1" class="col-md-3 control-label">Type of Paper</label>
<div class="col-md-9">
<select class="form-control" id="Otop" name="Otop" required>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
</select>
</div>
</div>
<div class="col-md-12">
<div class="form-input">
<label for="exampleSelect1" class="col-md-3 control-label">Paper upload</label>
<div class="col-md-9">
<input type="file" id="file" name="profileImg" >
</div>
</div>
</div>
<div class="form-input">
<div class="col-sm-12">
<input type="submit" class="btn btn-primary btn-lg btn-block" onclick="mycall()" name="OrderSubmit" value="Order">
</div>
</div>
</form>
</body>
</html>
addToMySQL.php
<?php
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
include("dbconfig.php");
include('class/userClass.php');
$userClass = new userClass();
$Otop = $_POST['Otop'];
$Odiscipline = $_FILES['profileImg']['name'];
$target = "uploads/";
$fileTarget = $target.$Odiscipline;
$result = move_uploaded_file($_FILES['profileImg']['tmp_name'], "uploads/".$_FILES['profileImg']['name']);
$id = $userClass->userOrderInfo($Otop,$Odiscipline, $fileTarget);
if ($id) {
echo "done";
} else {
echo "Notdone";
}
userOrderInfo fuction in userClass.php
/* User Payment */
public function userOrderInfo($Otop, $Odiscipline, $fileTarget)
{
try {
$db = getDB();
$stmt = $db->prepare("INSERT INTO orderinfo(Otop, Odiscipline, fileTarget) VALUES (:Otop, :Odiscipline, :fileTarget)");
$stmt->bindParam("Odiscipline", $Odiscipline) ;
$stmt->bindParam("Otop", $Otop) ;
$stmt->bindParam("fileTarget", $fileTarget) ;
$stmt->execute();
$db = null;
return true;
} catch(PDOException $e) {
echo '{"error":{"text":'. $e->getMessage() .'}}';
}
}
Was meinst du damit, dass es nicht funktioniert? Sagen Sie uns die spezifischen Details –
@CamiloGo ya nach Ajax erfolgreich es nicht zu try.php gehen, die Form Aktion ist. –
Ich sehe kein Element mit ID = Daten .. – scaisEdge