C# HP QC ALM-REST-API: Anhänge auf Fehler hochladen

Question

Ich arbeite an ASP.Net-Projekt. Ich muss einen Anhang zu dem Fehler in HP QC ALM 12.5x hochladen.

Authentifizierung Teil ist bereits fertig und erfolgreich funktioniert.

Auf Defekt an der Befestigungs Hochladen Empfang WebException was unhandled: The remote server returned an error: (415) Unsupported Media Type.

ich den Code unten geschrieben haben

string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x"); 
byte[] boundaryBytes = System.Text.Encoding.ASCII.GetBytes("--" + boundary + "\r\n"); 

HttpWebRequest request = (HttpWebRequest)WebRequest.Create(HPALMUrl + "/rest/domains/" + HPALMDomain + "/projects/" + HPALMProject + "/attachments"); 
request.Method = "POST"; 
request.Accept = "application/json"; 
request.Headers.Add("Accept-Language", "en-US"); 
request.Headers.Add("Accept-Encoding", "gzip, deflate, sdch"); 
request.UserAgent = "Mozilla/5.0 (compatible; MSIE 10.0; Windows NT 6.1; WOW64; Trident/6.0)"; 
request.ContentType = "Content-Type: multipart/form-data; boundary=" + boundary; 
request.AllowWriteStreamBuffering = false; 
request.ContentLength = imageBytes.Length; 
authRequest.KeepAlive = true; 
request.CookieContainer = createSessionRequest.CookieContainer; //successfully authenticated cookie 

string contentDisposition = "form-data; entity.type=\"{0}\"; entity.id=\"{1}\"; filename=\"{2}\"; Content-Type=\"{3}\""; 
request.Headers.Add("Content-Disposition", string.Format(contentDisposition, "defect", "4", "Defect Attachment.png", "application/octet-stream")); //I am not clear with passing content disposition. Please let me know if this should be modified. 

Ich versuche, wie Bild-Datei laden unter

string path = @"C:\TestAttachment.png"; 
byte[] imageBytes = System.IO.File.ReadAllBytes(path); 
using (Stream requestStream = request.GetRequestStream()) 
{ 
    requestStream.Write(boundaryBytes, 0, boundaryBytes.Length); 
    using (MemoryStream memoryStream = new MemoryStream(imageBytes)) 
    { 
     byte[] buffer = new byte[imageBytes.Length]; 
     int bytesRead = 0; 
     while ((bytesRead = memoryStream.Read(buffer, 0, buffer.Length)) != 0) 
     { 
      requestStream.Write(buffer, 0, bytesRead); 
     } 
    } 
} 

var response = (HttpWebResponse)request.GetResponse(); //Receiving Error here 

string responseText = string.Empty; 
if (response.StatusCode == HttpStatusCode.OK) 
    responseText = "Update completed"; 
else 
    responseText = "Error in update"; 

Sie mich bitte, was ich falsch mache.

Ich bin auch unsicher, die Inhaltsdisposition zu übergeben, die in rest api erwähnt wird.

Vielen Dank im Voraus!

Answer 1

def upload_result_file(self, defect_id, report_file): 
    ''' 
     Function : upload_result_file 
     Description : Upload test result to ALM 
    ''' 
    payload = open(report_file, 'rb') 
    headers = {} 
    headers['Content-Type'] = "application/octet-stream" 
    headers['slug'] = "test-results" + report_file[report_file.rfind(".")+1: ] 
    response = self.alm_session.post(ALM_URL + ALM_MIDPOINT + "/defects/" + 
            str(defect_id) + "/attachments/", 
            headers=headers, data=payload) 
    if not (response.status_code == 200 or response.status_code == 201): 
     print "Attachment step failed!", response.text, response.url, response.status_code 
    return