Ich verwende eine Open-Source-Methode, die den HTML-Text in einen NSString analysiert.Open-Source-HTML-Parsing-Klasse Parsing Leerzeichen zwischen Absätzen nicht korrekt
Die resultierenden Zeichenfolgen weisen zwischen den ersten paar Absätzen große Leerräume auf, aber nur eine Leerzeile für nachfolgende Absätze. Hier ist ein Beispiel für eine Ausgabe.
Unten ist die Methode, die ich anrufe. Ich habe nur zwei Zeilen des Codes geändert. Für stopCharacters
und newLineAndWhitespaceCharacters
entfernte ich /n
aus dem Zeichensatz, denn wenn es enthalten war, war der gesamte Text ein langer Absatz.
- (NSString *)stringByConvertingHTMLToPlainText {
// Pool
NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init];
// Character sets
NSCharacterSet *stopCharacters = [NSCharacterSet characterSetWithCharactersInString:[NSString stringWithFormat:@"< \t\r%C%C%C%C", 0x0085, 0x000C, 0x2028, 0x2029]];
NSCharacterSet *newLineAndWhitespaceCharacters = [NSCharacterSet characterSetWithCharactersInString:[NSString stringWithFormat:@" \t\r%C%C%C%C", 0x0085, 0x000C, 0x2028, 0x2029]];
NSCharacterSet *tagNameCharacters = [NSCharacterSet characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"];
// Scan and find all tags
NSMutableString *result = [[NSMutableString alloc] initWithCapacity:self.length];
NSScanner *scanner = [[NSScanner alloc] initWithString:self];
[scanner setCharactersToBeSkipped:nil];
[scanner setCaseSensitive:YES];
NSString *str = nil, *tagName = nil;
BOOL dontReplaceTagWithSpace = NO;
do {
// Scan up to the start of a tag or whitespace
if ([scanner scanUpToCharactersFromSet:stopCharacters intoString:&str]) {
[result appendString:str];
str = nil; // reset
}
// Check if we've stopped at a tag/comment or whitespace
if ([scanner scanString:@"<" intoString:NULL]) {
// Stopped at a comment or tag
if ([scanner scanString:@"!--" intoString:NULL]) {
// Comment
[scanner scanUpToString:@"-->" intoString:NULL];
[scanner scanString:@"-->" intoString:NULL];
} else {
// Tag - remove and replace with space unless it's
// a closing inline tag then dont replace with a space
if ([scanner scanString:@"/" intoString:NULL]) {
// Closing tag - replace with space unless it's inline
tagName = nil; dontReplaceTagWithSpace = NO;
if ([scanner scanCharactersFromSet:tagNameCharacters intoString:&tagName]) {
tagName = [tagName lowercaseString];
dontReplaceTagWithSpace = ([tagName isEqualToString:@"a"] ||
[tagName isEqualToString:@"b"] ||
[tagName isEqualToString:@"i"] ||
[tagName isEqualToString:@"q"] ||
[tagName isEqualToString:@"span"] ||
[tagName isEqualToString:@"em"] ||
[tagName isEqualToString:@"strong"] ||
[tagName isEqualToString:@"cite"] ||
[tagName isEqualToString:@"abbr"] ||
[tagName isEqualToString:@"acronym"] ||
[tagName isEqualToString:@"label"]);
}
// Replace tag with string unless it was an inline
if (!dontReplaceTagWithSpace && result.length > 0 && ![scanner isAtEnd]) [result appendString:@" "];
}
// Scan past tag
[scanner scanUpToString:@">" intoString:NULL];
[scanner scanString:@">" intoString:NULL];
}
} else {
// Stopped at whitespace - replace all whitespace and newlines with a space
if ([scanner scanCharactersFromSet:newLineAndWhitespaceCharacters intoString:NULL]) {
if (result.length > 0 && ![scanner isAtEnd]) [result appendString:@" "]; // Dont append space to beginning or end of result
}
}
} while (![scanner isAtEnd]);
// Cleanup
[scanner release];
// Decode HTML entities and return
NSString *retString = [[result stringByDecodingHTMLEntities] retain];
[result release];
// Drain
[pool drain];
// Return
return [retString autorelease];
}
EDIT:
Hier ist die NSLog der Zeichenfolge. Ich klebte nur die ersten paar Absätze
Mitt Romney spent the past six years running for president. After his loss to President Barack Obama, he'll have to chart a different course.
His initial plan: spend time with his family. He has five sons and 18 grandchildren, with a 19th on the way.
"I don't look at postelection to be a time of regrouping. Instead it's a time of forward focus," Romney told reporters aboard his plane Tuesday evening as he returned to Boston after the final campaign stop of his political career. "I have, of course, a family and life important to me, win or lose."
The most visible member of that family — wife Ann Romney — says neither she nor her husband will seek political office again.
etc ....
for (int j = 25; j< 50; j++) {
char test = [completeTrimmed characterAtIndex:([completeTrimmed rangeOfString:@"chart a different course."].location + j)];
NSLog(@"%hhd", test);
}
012-11-11 17:15:57.668 LMU_LAL_LAUNCHER[5431:c07] 32
2012-11-11 17:15:57.669 LMU_LAL_LAUNCHER[5431:c07] 32
2012-11-11 17:15:57.669 LMU_LAL_LAUNCHER[5431:c07] 10
2012-11-11 17:15:57.670 LMU_LAL_LAUNCHER[5431:c07] 32
2012-11-11 17:15:57.670 LMU_LAL_LAUNCHER[5431:c07] 32
2012-11-11 17:15:57.670 LMU_LAL_LAUNCHER[5431:c07] 10
2012-11-11 17:15:57.671 LMU_LAL_LAUNCHER[5431:c07] 32
2012-11-11 17:15:57.671 LMU_LAL_LAUNCHER[5431:c07] 32
2012-11-11 17:15:57.671 LMU_LAL_LAUNCHER[5431:c07] 10
2012-11-11 17:15:57.672 LMU_LAL_LAUNCHER[5431:c07] 32
2012-11-11 17:15:57.672 LMU_LAL_LAUNCHER[5431:c07] 72
2012-11-11 17:15:57.672 LMU_LAL_LAUNCHER[5431:c07] 105
2012-11-11 17:15:57.673 LMU_LAL_LAUNCHER[5431:c07] 115
2012-11-11 17:15:57.673 LMU_LAL_LAUNCHER[5431:c07] 32
2012-11-11 17:15:57.673 LMU_LAL_LAUNCHER[5431:c07] 105
2012-11-11 17:15:57.673 LMU_LAL_LAUNCHER[5431:c07] 110
2012-11-11 17:15:57.674 LMU_LAL_LAUNCHER[5431:c07] 105
2012-11-11 17:15:57.674 LMU_LAL_LAUNCHER[5431:c07] 116
2012-11-11 17:15:57.674 LMU_LAL_LAUNCHER[5431:c07] 105
2012-11-11 17:15:57.675 LMU_LAL_LAUNCHER[5431:c07] 97
2012-11-11 17:15:57.675 LMU_LAL_LAUNCHER[5431:c07] 108
2012-11-11 17:15:57.675 LMU_LAL_LAUNCHER[5431:c07] 32
2012-11-11 17:15:57.675 LMU_LAL_LAUNCHER[5431:c07] 112
2012-11-11 17:15:57.676 LMU_LAL_LAUNCHER[5431:c07] 108
2012-11-11 17:15:57.676 LMU_LAL_LAUNCHER[5431:c07] 97
Wahrscheinlich müssen Sie die stringByReplacingCharactersInRange-Methode verwenden, um zusätzliche Leerzeichen aus der letzten Zeichenfolge zu entfernen. – iDev
Ich habe bereits versucht 'completeTrimmed = [completeTrimmed stringByReplacingOccurrencesOfString: @„‚withString: @‘ ‚];', aber es tut nichts – Mahir
@‘“ sollte etwa 15 Räume dazwischen, haben aber den Kommentar autocorrects es 1 Leerzeichen – Mahir