2017-09-29 2 views
3

Ich bin sehr neu in der Entwicklung und konnte nicht viel Ende-zu-Ende-Unterstützung zu diesem Thema finden. Ich habe getan, was ich mit Hilfe der Firebase-Hilfeseite konnte. Ich kann keine Benachrichtigungen auf meinen iOS-Geräten empfangen, aber FCM funktioniert perfekt auf Android. Hier ist meine AppDelegate von XcodePush-Benachrichtigungen in iOS mit Firebase und PHP

import UIKit 
import Firebase 
import FirebaseMessaging 
import UserNotifications 

@UIApplicationMain 
class AppDelegate: UIResponder, UIApplicationDelegate, UNUserNotificationCenterDelegate { 

    var window: UIWindow? 


    func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool { 
     UIApplication.shared.applicationIconBadgeNumber = 0 
     // Override point for customization after application launch. 
     if #available(iOS 10.0, *) { 
      // For iOS 10 display notification (sent via APNS) 
      UNUserNotificationCenter.current().delegate = self 

      let authOptions: UNAuthorizationOptions = [.alert, .badge, .sound] 
      UNUserNotificationCenter.current().requestAuthorization(
       options: authOptions, 
       completionHandler: {_, _ in }) 

      // For iOS 10 data message (sent via FCM) 
      //FIRMessaging.messaging().remoteMessageDelegate = self 

     } else { 
      let settings: UIUserNotificationSettings = 
       UIUserNotificationSettings(types: [.alert, .badge, .sound], categories: nil) 
      UIApplication.shared.registerUserNotificationSettings(settings) 
      UIApplication.shared.registerForRemoteNotifications() 
     } 

     application.registerForRemoteNotifications() 

     FirebaseApp.configure() 
     return true 
    } 

    func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) { 
     let token1 = Messaging.messaging().fcmToken 
     print("FCM token: \(token1 ?? "")") 
     var request = URLRequest(url: URL(string: "http://www.myurl.com/register.php")!) 
     request.httpMethod = "POST" 
     let postString = "Token="+token1! 
     request.httpBody = postString.data(using: .utf8) 
     let task = URLSession.shared.dataTask(with: request) { data, response, error in 
      guard let data = data, error == nil else {             // check for fundamental networking error 
       print("error=\(String(describing: error))") 
       return 
      } 

      if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 {   // check for http errors 
       print("statusCode should be 200, but is \(httpStatus.statusCode)") 
       print("response = \(String(describing: response))") 
      } 

      let responseString = String(data: data, encoding: .utf8) 
      print("responseString = \(String(describing: responseString))") 
     } 
     task.resume() 
    } 

    func application(_ application: UIApplication, didFailToRegisterForRemoteNotificationsWithError error: Error) { 
     print("Registration failed!") 
    } 

    func applicationWillResignActive(_ application: UIApplication) { 
     // Sent when the application is about to move from active to inactive state. This can occur for certain types of temporary interruptions (such as an incoming phone call or SMS message) or when the user quits the application and it begins the transition to the background state. 
     // Use this method to pause ongoing tasks, disable timers, and invalidate graphics rendering callbacks. Games should use this method to pause the game. 
    } 

    func applicationDidEnterBackground(_ application: UIApplication) { 
     // Use this method to release shared resources, save user data, invalidate timers, and store enough application state information to restore your application to its current state in case it is terminated later. 
     // If your application supports background execution, this method is called instead of applicationWillTerminate: when the user quits. 
    } 

    func applicationWillEnterForeground(_ application: UIApplication) { 
     // Called as part of the transition from the background to the active state; here you can undo many of the changes made on entering the background. 
    } 

    func applicationDidBecomeActive(_ application: UIApplication) { 
     // Restart any tasks that were paused (or not yet started) while the application was inactive. If the application was previously in the background, optionally refresh the user interface. 
    } 

    func applicationWillTerminate(_ application: UIApplication) { 
     // Called when the application is about to terminate. Save data if appropriate. See also applicationDidEnterBackground:. 
    } 

    @available(iOS 10.0, *) 
    func userNotificationCenter(_ center: UNUserNotificationCenter, willPresent notification: UNNotification, withCompletionHandler completionHandler: @escaping (_ options: UNNotificationPresentationOptions) -> Void) { 

     // custom code to handle push while app is in the foreground 
     print("Handle push from foreground\(notification.request.content.userInfo)") 

     let dict = notification.request.content.userInfo["aps"] as! NSDictionary 
     let d : [String : Any] = dict["alert"] as! [String : Any] 
     let body : String = d["body"] as! String 
     let title : String = d["title"] as! String 
//  print("Title:\("FOSG NOTIFICATION") + body:\(body)") 
     self.showAlertAppDelegate(title: "Federation Of Safety Glass",message:body,buttonTitle:"ok",window:self.window!) 

    } 

    @available(iOS 10.0, *) 
    func userNotificationCenter(_ center: UNUserNotificationCenter, didReceive response: UNNotificationResponse, withCompletionHandler completionHandler: @escaping() -> Void) { 
     // if you set a member variable in didReceiveRemoteNotification, you will know if this is from closed or background 
     print("Handle push from background or closed\(response.notification.request.content.userInfo)") 
    } 

    func showAlertAppDelegate(title: String,message : String,buttonTitle: String,window: UIWindow){ 
     let alert = UIAlertController(title: title, message: message, preferredStyle: UIAlertControllerStyle.alert) 
     alert.addAction(UIAlertAction(title: buttonTitle, style: UIAlertActionStyle.default, handler: nil)) 
     window.rootViewController?.present(alert, animated: false, completion: nil) 
    } 
    // Firebase ended here 

} 

und dies ist mein Code vom Server Ende auf php

$tokens = array(); $mess = ''; 
    // queries from db to set the values of variables. 
    function send_notification ($tokens, $message) 
    { 
     $url = 'https://fcm.googleapis.com/fcm/send'; 
     $fields = array(
      'registration_ids' => $tokens, 
      'data' => $message 
      ); 
     $headers = array(
      'Authorization:key = **key ', 
      'Content-Type: application/json' 
      ); 
     $ch = curl_init(); 
     curl_setopt($ch, CURLOPT_URL, $url); 
     curl_setopt($ch, CURLOPT_POST, true); 
     curl_setopt($ch, CURLOPT_HTTPHEADER, $headers); 
     curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 
     curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0); 
     curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false); 
     curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode($fields)); 
     $result = curl_exec($ch);   
     if ($result === FALSE) { 
      die('Curl failed: ' . curl_error($ch)); 
     } 
     curl_close($ch); 
     return $result; 
    } 
    $message = array(
     "body" => $mess, 
     "message" => $mess, 
     "title" => "FOSG NOTIFICATION", 
     "sound" => 1, 
     "vibrate" => 1, 
     "badge" => 1, 
    ); 
    $t = implode('',$tokens); 
    if(t != '') $message_status = send_notification($tokens, $message); 

Bitte helfen Sie mir meine Frage

+0

prüfen diese Kurz out: https://github.com/firebase/quickstart-ios/tree/master/messaging es hat mir geholfen Nachrichten einrichten. Versuchen Sie dann, eine Nachricht von der Firebase-Konsole zu senden, und stellen Sie sicher, dass das funktioniert. Das wird helfen, einzugrenzen, wenn das Problem mit dem Swift-Code oder PHP zusammenhängt. –

+0

Vielen Dank für Ihre Antwort Jen. Ich konnte den Fehler nicht mit der von Ihnen bereitgestellten Github-Quelle finden. Aber Firebase-Konsole sendet die Benachrichtigungen erfolgreich, es ist nur, wenn ich sie über mein Server-Skript sende, bekomme ich nichts. – Sarabjit

+0

Das erste, was mir einfällt, ist, dass Sie nicht das richtige Zertifikat auf Firebase hochgeladen haben. Sie könnten versuchen, dies zu überprüfen. –

Antwort

3

Nur die Feldnamen geändert zu lernen und zu lösen, bevor das Senden die JSON

ändern Sie die folgenden:

$fields = array(
      'registration_ids' => $tokens, 
      'data' => $message 
      ); 

zu

$fields = array(
      'registration_ids' => $tokens, 
      'notification' => $message, 
      'priority' => 'high' 
      );