SQLiteException: in der Nähe von "": Syntaxfehler (Code 1) beim Kompilieren

Question

Ich habe diesen Fehler beim Kompilieren und ich weiß nicht warum, kann mir jemand helfen?

public static final Zeichenfolge TABLE_BEERS = "cervezas";

// Contacts Table Columns names 
public static final String KEY_NAME = "_id"; 
public static final String KEY_COMPANY = "company"; 
public static final String KEY_TYPE = "type"; 
public static final String KEY_ALCOHOL = "alcohol"; 


public DatabaseHandler(Context context) { 
    super(context, DATABASE_NAME, null, DATABASE_VERSION); 
    // TODO Auto-generated constructor stub 
} 

@Override 
public void onCreate(SQLiteDatabase db) { 

    String query = String.format("CREATE TABLE %s (%s STRING PRIMARY KEY,%s TEXT, %s TEXT, %s TEXT);", 
      TABLE_BEERS, KEY_NAME, KEY_COMPANY, 
      KEY_TYPE, KEY_ALCOHOL); 

    /* 
    String CREATE_BEER_TABLE = "create table " + TABLE_BEERS + "(" 
      + KEY_NAME + " STRING PRIMARY KEY," 
      + KEY_COMPANY + " TEXT," 
      + KEY_TYPE + " TEXT," 
      + KEY_ALCOHOL + " TEXT)";*/ 
    db.execSQL(query); 

Dies ist für die Tabelle erstellen

public List<Cervezas> getCompanyCervezas(String compania){ 

      List<Cervezas> cervezasList = new ArrayList<Cervezas>(); 
      // Select All Query 
      String selectQuery = "SELECT _id, type, alcohol FROM " + TABLE_BEERS + " WHERE company=" + compania; 

      SQLiteDatabase db = this.getReadableDatabase(); 
      Cursor cursor = db.rawQuery(selectQuery, null); 

LogCat

android.database.sqlite.SQLiteException: no such column : Alean (code 1): , while compiling: SELECT _id, type, alcohol FROM cervezas WHERE company=Alean 

Was geschieht?

Answer 1

versuchen Code unten: -

String selectQuery = "SELECT _id, type, alcohol FROM " + TABLE_BEERS + " WHERE company= ' " + compania+" ' "; 

Sie einfache Anführungszeichen verpassen ..

Answer 2

Text Spaltenwerte in einfache Anführungszeichen passieren muss. Versuchen Sie folgendes:

String selectQuery = "SELECT _id, type, alcohol FROM " + TABLE_BEERS + " WHERE company= '" + compania +"'";