Die „einfache“ Antwort auf diese, reine VBScript unter der Annahme, war ein bignum addieren und multiplizieren und dann berechnen Sie die Antwort auf diese Weise zu schreiben.
Code von RosettaCode, ich habe die folgende VeryLargeInteger Klasse erstellt und eine Hex64 Funktion, die sagt, dass 4702170486407730494 die 64-Bit-Dezimaläquivalents von 0x41417724EBA8953E ist
Option Explicit
Class VeryLongInteger
'http://rosettacode.org/wiki/Long_Multiplication#Liberty_BASIC
Public Function MULTIPLY(Str_A, Str_B)
Dim signA, signB, sResult, Str_Shift, i, d, Str_T
signA = 1
If Left(Str_A,1) = "-" Then
Str_A = Mid(Str_A,2)
signA = -1
End If
signB = 1
If Left(Str_B,1) = "-" Then
Str_B = Mid(Str_B,2)
signB = -1
End If
sResult = vbNullString
Str_T = vbNullString
Str_shift = vbNullString
For i = Len(Str_A) To 1 Step -1
d = CInt(Mid(Str_A,i,1))
Str_T = MULTBYDIGIT(Str_B, d)
sResult = ADD(sResult, Str_T & Str_shift)
Str_shift = Str_shift & "0"
'print d, Str_T, sResult
Next
If signA * signB < 0 Then sResult = "-" + sResult
'print sResult
MULTIPLY = sResult
End Function
Private Function MULTBYDIGIT(Str_A, d)
Dim sResult, carry, i, a, c
'multiply Str_A by digit d
sResult = vbNullString
carry = 0
For i = Len(Str_A) To 1 Step -1
a = CInt(Mid(Str_A,i,1))
c = a * d + carry
carry = c \ 10
c = c Mod 10
'print a, c
sResult = CStr(c) & sResult
Next
If carry > 0 Then sResult = CStr(carry) & sResult
'print sResult
MULTBYDIGIT = sResult
End Function
Public Function ADD(Str_A, Str_B)
Dim L, sResult, carry, i, a, b, c
'add Str_A + Str_B, for now only positive
l = MAX(Len(Str_A), Len(Str_B))
Str_A=PAD(Str_A,l)
Str_B=PAD(Str_B,l)
sResult = vbNullString 'result
carry = 0
For i = l To 1 Step -1
a = CInt(Mid(Str_A,i,1))
b = CInt(Mid(Str_B,i,1))
c = a + b + carry
carry = Int(c/10)
c = c Mod 10
'print a, b, c
sResult = CStr(c) & sResult
Next
If carry>0 Then sResult = CStr(carry) & sResult
'print sResult
ADD = sResult
End Function
Private Function Max(a,b)
If a > b Then
Max = a
Else
Max = b
End If
End Function
Private Function pad(a,n) 'pad from right with 0 to length n
Dim sResult
sResult = a
While Len(sResult) < n
sResult = "0" & sResult
Wend
pad = sResult
End Function
End Class
Function Hex64(sHex)
Dim VLI
Set VLI = New VeryLongInteger
Dim Sixteen(16)
Sixteen(0) = "1"
Sixteen(1) = "16"
Sixteen(2) = VLI.MULTIPLY(Sixteen(1),"16")
Sixteen(3) = VLI.MULTIPLY(Sixteen(2),"16")
Sixteen(4) = VLI.MULTIPLY(Sixteen(3),"16")
Sixteen(5) = VLI.MULTIPLY(Sixteen(4),"16")
Sixteen(6) = VLI.MULTIPLY(Sixteen(5),"16")
Sixteen(7) = VLI.MULTIPLY(Sixteen(6),"16")
Sixteen(8) = VLI.MULTIPLY(Sixteen(7),"16")
Sixteen(9) = VLI.MULTIPLY(Sixteen(8),"16")
Sixteen(10) = VLI.MULTIPLY(Sixteen(9),"16")
Sixteen(11) = VLI.MULTIPLY(Sixteen(10),"16")
Sixteen(12) = VLI.MULTIPLY(Sixteen(11),"16")
Sixteen(13) = VLI.MULTIPLY(Sixteen(12),"16")
Sixteen(14) = VLI.MULTIPLY(Sixteen(13),"16")
Sixteen(15) = VLI.MULTIPLY(Sixteen(14),"16")
Dim theAnswer, i, theDigit, theMultiplier, thePower, aPower
theAnswer = "0"
aPower = 0
For i = Len(sHex) To 1 Step -1
theDigit = UCase(Mid(sHex,i,1))
theMultiplier = InStr("ABCDEF",theDigit)-1
thePower = Sixteen(aPower)
thePower = VLI.MULTIPLY(CStr(theMultiplier),thePower)
theAnswer = VLI.ADD(theAnswer,thePower)
aPower = aPower + 1
Next
Hex64 = theAnswer
End Function
WScript.Echo Hex64("41417724EBA8953E")
Ich möchte sagen, „genießen“, aber Seit dem ursprünglichen Posting sind mehr als sechs Monate vergangen, sodass Sie wahrscheinlich eine andere Lösung gefunden haben. Trotzdem hat es Spaß gemacht.
SPÄTER
Der andere Weg, um die Hex64 zu tun, wenn Sie die Vorkalkulation der Befugnisse von 16 vermeiden wollen ist:
Function Hex64b(sHex)
Dim VLI
Set VLI = New VeryLongInteger
Dim theAnswer, i, theDigit, theMultiplier, thePower, aPower
theAnswer = "0"
thePower = "1"
For i = Len(sHex) To 1 Step -1
theDigit = UCase(Mid(sHex,i,1))
theMultiplier = InStr("ABCDEF",theDigit)-1
theAnswer = VLI.ADD(theAnswer,VLI.MULTIPLY(thePower,theMultiplier))
thePower = VLI.MULTIPLY(thePower,"16")
Next
Hex64b = theAnswer
End Function