Python - Ein Fast Port Scanner

Question

So einen Port-Scanner in Python Ich mache ...

import socket 
ip = "External IP" 
s = socket.socket(2, 1) #socket.AF_INET, socket.SOCK_STREAM 

def porttry(ip, port): 
    try: 
     s.connect((ip, port)) 
     return True 
    except: 
     return None 

for port in range(0, 10000): 
    value = porttry(ip, port) 
    if value == None: 
     print("Port not opened on %d" % port) 
    else: 
     print("Port opened on %d" % port) 
     break 
raw_input() 

Aber das ist zu langsam, ich will irgendwie in der Lage sein, einige, wie nah oder brechen Code nach eine Zeitspanne, in der nichts zurückgegeben wird. Wenn dies nicht möglich ist, bitte hilf mir so oder so

Answer 1

Zusätzlich zur Einstellung Socket-Timeout können Sie auch Multi-Threading-Technik anwenden Turbo verstärkt den Prozess. Es ist bestenfalls N-mal schneller, wenn Sie N Ports zum Scannen haben.

# This script runs on Python 3 
import socket, threading 


def TCP_connect(ip, port_number, delay, output): 
    TCPsock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) 
    TCPsock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) 
    TCPsock.settimeout(delay) 
    try: 
     TCPsock.connect((ip, port_number)) 
     output[port_number] = 'Listening' 
    except: 
     output[port_number] = '' 



def scan_ports(host_ip, delay): 

    threads = []  # To run TCP_connect concurrently 
    output = {}   # For printing purposes 

    # Spawning threads to scan ports 
    for i in range(10000): 
     t = threading.Thread(target=TCP_connect, args=(host_ip, i, delay, output)) 
     threads.append(t) 

    # Starting threads 
    for i in range(10000): 
     threads[i].start() 

    # Locking the script until all threads complete 
    for i in range(10000): 
     threads[i].join() 

    # Printing listening ports from small to large 
    for i in range(10000): 
     if output[i] == 'Listening': 
      print(str(i) + ': ' + output[i]) 



def main(): 
    host_ip = input("Enter host IP: ") 
    delay = int(input("How many seconds the socket is going to wait until timeout: ")) 
    scan_ports(host_ip, delay) 

if __name__ == "__main__": 
    main() 

Answer 2

Ich denke, dass dies ein Snippet Ihnen helfen könnten: http://www.coderholic.com/python-port-scanner/

Answer 3

Betrachten wir ein Timeout statt einer for-Schleife Einstellung von socket.setdefaulttimeout(timeout) verwenden.

Answer 4

socket.setdefaulttimeout (0.5) Dies wird das Programm schneller machen!

Answer 5

socket.setdefualttimeout (Zeit)

wird verwendet, mit Anschluss zu halten versuchen, für perticular Zeit zu verbinden ..., wenn Sie Anfrage senden und es ist Timeout Set für 2 Sekunden, so dass es mit dem Anschluss zu verbinden versuchen, für 2 Sekunden .... wenn es keine Antwort von diesem Port in 2 Sekunden gibt .... wird es als ein toter Port zählen

Answer 6

Dies sollte ein bisschen schneller sein.

#-*-coding:utf8;-*- 
#qpy:3 
#qpy:console 

import socket 
import os 

# This is used to set a default timeout on socket 
# objects. 
DEFAULT_TIMEOUT = 0.5 

# This is used for checking if a call to socket.connect_ex 
# was successful. 
SUCCESS = 0 

def check_port(*host_port, timeout=DEFAULT_TIMEOUT): 
    ''' Try to connect to a specified host on a specified port. 
    If the connection takes longer then the TIMEOUT we set we assume 
    the host is down. If the connection is a success we can safely assume 
    the host is up and listing on port x. If the connection fails for any 
    other reason we assume the host is down and the port is closed.''' 

    # Create and configure the socket. 
    sock = socket.socket() 
    sock.settimeout(timeout) 

    # the SO_REUSEADDR flag tells the kernel to reuse a local 
    # socket in TIME_WAIT state, without waiting for its natural 
    # timeout to expire. 
    sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) 

    # Like connect(address), but return an error indicator instead 
    # of raising an exception for errors returned by the C-level connect()  
    # call (other problems, such as “host not found,” can still raise exceptions). 
    # The error indicator is 0 if the operation succeeded, otherwise the value of 
    # the errnovariable. This is useful to support, for example, asynchronous connects. 
    connected = sock.connect_ex(host_port) is SUCCESS 

    # Mark the socket closed. 
    # The underlying system resource (e.g. a file descriptor) 
    # is also closed when all file objects from makefile() are closed. 
    # Once that happens, all future operations on the socket object will fail. 
    # The remote end will receive no more data (after queued data is flushed). 
    sock.close() 

    # return True if port is open or False if port is closed. 
    return connected 


con = check_port('www.google.com', 83) 
print(con)