Rate die Zahl in Python. Option zum Schließen des Spiels

Question

Ich bin neu in Python und Programmierung und ich versuche, das Spiel "Raten Sie die Zahl" zu machen. Ich habe es funktioniert, aber ich möchte die Option hinzufügen, um das Spiel mit der Bremse Anweisung zu schließen. Ich habe seit 2 Tagen versucht, aber ich denke, ich bin steckengeblieben. Hier

ist der Code, der funktioniert (ohne die Möglichkeit, das Spiel zu schließen):

import random 
attempts = 0 
secretNumber = random.randint(1,100) 
while True: 
    print("Guess a number between 1 and 100") 
    guess=input() 
    guess = int(guess) 
    attempts = attempts + 1 
    if guess >100 or guess<=0: 
     attempts = attempts - 1 
     print("Not allowed.Only numbers between 1 and 100 allowed! \n") 
    elif guess < secretNumber and guess >0: 
     print("Nope!Try a higher number! \n") 
    elif guess > secretNumber and guess <100: 
     print("Nope!Try a lower number \n") 
    if guess == secretNumber: 
     break 

if guess == secretNumber: 
      attempts = str(attempts) 
print("Congratulations you found it after " + attempts + " attempts") 

-Code (mit der Option, das Spiel zu schließen), dass nicht funktioniert:

import random 
attempts = 0 
secretNumber = random.randint(1,100) 
while True: 
    print("Guess a number between 1 and 100. You can exit game anytime by typing quit ") 
    stop=input() 
    stop=str(stop) 
    if stop == "quit": 
     break 
     print("You quitted the game") 
    else: 
      continue 
    guess=input() 
    guess = int(guess) 
    attempts = attempts + 1 
    if guess >100 or guess<=0: 
     attempts = attempts - 1 
     print("Not allowed.Only numbers between 1 and 100 allowed! \n") 
    elif guess < secretNumber and guess >0: 
     print("Nope!Try a higher number! \n") 
    elif guess > secretNumber and guess <100: 
     print("Nope!Try a lower number \n") 
    if guess == secretNumber: 
     break 

if guess == secretNumber: 
      attempts = str(attempts) 
print("Congratulations you found it after " + attempts + " attempts") 

Ich bin Entschuldigung für die lange Post, jede Hilfe auf, was ich falsch mache oder sogar einen anderen Ansatz, um dies zu erreichen mit der brechen Anweisung und ohne die Def-Funktion verwenden wird sehr geschätzt werden. Vielen Dank im Voraus.

Answer 1

paar Änderungen und alles ist gut

import random 
attempts = 0 
secretNumber = random.randint(1,100) 
while True: 
    print("Guess a number between 1 and 100. You can exit game anytime by typing q ") 
    guess=input() 
    stop=str(guess) 
    if stop== 'q': 
     print("You quitted the game") 
     break 
    elif not guess.isdigit(): 
     print("Only numbers are allowed") 
    else:   
     guess = int(guess) 
     attempts = attempts + 1 
     if guess >100 or guess<=0: 
      attempts = attempts - 1 
      print("Not allowed.Only numbers between 1 and 100 allowed! \n") 
     elif guess < secretNumber and guess >0: 
      print("Nope!Try a higher number! \n") 
     elif guess > secretNumber and guess <100: 
      print("Nope!Try a lower number \n") 
     if guess == secretNumber: 
      attempts = str(attempts) 
      print("Congratulations you found it after " + attempts + " attempts") 
      break 

Answer 2

Unter was Nick A und timgeb in ihren Kommentaren erwähnt, Sie ein paar Dinge anpassen konnte. Wie ich im folgenden Skript vorschlage, möchten Sie vielleicht einen Blick auf try and except werfen. Bitte finden Sie Kommentare im Skript.

import random 
attempts = 0 
secretNumber = random.randint(1,100) 
# you can prompt the user within input() 
stop=input("Guess a number between 1 and 100. You can exit game anytime by typing quit ") 

while True: 
    if stop == "quit": # as the the output of input() is a string, you can compare it with a string without str() 
     print("You quitted the game") 
     break 
    try: # work with try and except to avoid problems whenever the user writes something else than 'quit' or an integer 
     guess = int(stop) 
     attempts += 1 
     if guess >100 or guess<=0: 
      attempts = attempts - 1 
      print("Not allowed.Only numbers between 1 and 100 allowed! \n") 
     elif guess < secretNumber and guess >0: 
      print("Nope!Try a higher number! \n") 
     elif guess > secretNumber and guess <=100: # note that it's <=. Otherwise nothing happens when the users chose 100 
      print("Nope!Try a lower number \n") 
    except: # if it's not possible to turn 'stop' into an integer we'd like to perform the following 
     stop = input("No valid input, please guess again ") # Don't stop the script, let the user guess again 
     continue # don't stop, but leave the current iteration (don't execute the rest) and start again at the beginning of the loop 
    if guess == secretNumber: 
     attempts = str(attempts) 
     print("Congratulations you found it after " + attempts + " attempts") 
     break 
    stop = input("Guess again ") # prompt for a new number every round of the loop