Die Daten aus der Firebase-Datenbank und dem Speicher können nicht entfernt werden.

Question

Ich verwende den folgenden Code zum Hochladen von Fotos und Daten zu Firebase.

static func sendDataToDatabase(photoUrl: String, videoUrl: String? = nil, ratio: CGFloat, caption: String, Location: String, onSuccess: @escaping() -> Void) { 
    let newPostId = Api.Post.REF_POSTS.childByAutoId().key 
    let newPostReference = Api.Post.REF_POSTS.child(newPostId) 

    guard let currentUser = Api.User.CURRENT_USER else { 
     return 
    } 

    let currentUserId = currentUser.uid 

    let words = caption.components(separatedBy: CharacterSet.whitespacesAndNewlines) 

    for var word in words { 
     if word.hasPrefix("#") { 
      word = word.trimmingCharacters(in: CharacterSet.punctuationCharacters) 
      let newHashTagRef = Api.HashTag.REF_HASHTAG.child(word.lowercased()) 
      newHashTagRef.updateChildValues([newPostId: true]) 
     } 
    } 

    let timestamp = Int(Date().timeIntervalSince1970) 

    var dict = ["uid": currentUserId ,"photoUrl": photoUrl, "caption": caption, "Location": Location, "likeCount": 0, "ratio": ratio, "timestamp": timestamp] as [String : Any] 
    if let videoUrl = videoUrl { 
     dict["videoUrl"] = videoUrl 
    } 

    newPostReference.setValue(dict, withCompletionBlock: { 
     (error, ref) in 
     if error != nil { 
      ProgressHUD.showError(error!.localizedDescription) 
      return 
     } 

     Api.Feed.REF_FEED.child(Api.User.CURRENT_USER!.uid).child(newPostId) 
      .setValue(["timestamp": timestamp]) 
     Api.Follow.REF_FOLLOWERS.child(Api.User.CURRENT_USER!.uid).observeSingleEvent(of: .value, with: { 
      snapshot in 
      let arraySnapshot = snapshot.children.allObjects as! [DataSnapshot] 
      arraySnapshot.forEach({ (child) in 
       print(child.key) 
       Api.Feed.REF_FEED.child(child.key).child(newPostId) 
        .setValue(["timestamp": timestamp]) 
       let newNotificationId = Api.Notification.REF_NOTIFICATION.child(child.key).childByAutoId().key 
       let newNotificationReference = Api.Notification.REF_NOTIFICATION.child(child.key).child(newNotificationId) 
       newNotificationReference.setValue(["from": Api.User.CURRENT_USER!.uid, "type": "feed", "objectId": newPostId, "timestamp": timestamp]) 
      }) 
     }) 
     let myPostRef = Api.MyPosts.REF_MYPOSTS.child(currentUserId).child(newPostId) 
     myPostRef.setValue(["timestamp": timestamp], withCompletionBlock: { (error, ref) in 
      if error != nil { 
       ProgressHUD.showError(error!.localizedDescription) 
       return 
      } 
     }) 
     ProgressHUD.showSuccess("Success") 
     onSuccess() 
    }) 
} 

Verwendung Taste und unter Code zum Löschen Foto und nehmen Sie Daten von Firebase

@IBAction func DeletePost(_ sender: Any) { 

    guard let currentUser = Api.User.CURRENT_USER else { 
     return 
    } 

    let newPostId = Api.Post.REF_POSTS.childByAutoId().key 
    let currentUserId = currentUser.uid 
    let newPostReference = Api.Post.REF_POSTS.child(newPostId) 

    let alert = UIAlertController(title: "Delete Post", message: "Are You Sure ?", preferredStyle: .alert); 

    alert.addAction(UIAlertAction(title: "Cancel", style: .cancel, handler: nil)); 

    let okAction = UIAlertAction(title: "Delete", style: .default) {(action) in 
     Api.MyPosts.REF_MYPOSTS.child(currentUserId).child(newPostId).removeValue() 

    { (error, ref) in 
     if error != nil { 
     print("error") 
     return 
     } 
     print("Posts Deleted") 
     } 

    }; 
     alert.addAction(okAction); 

    self.present(alert, animated: true, completion: nil); 

     } 

Projekt gut laufen, aber wenn Touch-Taste zum Löschen Post nichts passiert!

Api.MyPosts.REF_MYPOSTS.child (CurrentUserID) .child (newPostId) .removeValue()

Dieser Code haben kein Problem und muss arbeiten gut so, wo ist das Problem?

Answer 1

den Code unten Versuchen:

var photoRef = DatabaseReference() 

Put in ViewDidLoad:

photoRef = Database.database().reference().child("posts") 

Sie haben müssen die The_Unique_id gespeichert somewhere.And Sie die URL des Bildes werden mit dass Sie löschen möchten.

Klicken Sie auf Ihre Schaltfläche: statusRef.child("The_Unique_id").child("Pass_Your_imageUrl_Here").removeValue().

Answer 2

Versuchen Sie, diese

Api.MyPosts.REF_MYPOSTS.child(currentUserId).removeValue() 
Api.MyPosts.REF_MYPOSTS.child(newPostId).removeValue()