Codeigniter 3: Array-Formular in Datenbank einfügen

Question

Ich bin neu mit Codeigniter und habe Probleme beim Einfügen von Arrays in meine Datenbank. Es ist ein Fehler aufgetreten, dass ich das Array nicht in meine Datenbank einfügen kann.

Hier ist mein HTML-Formular:

<?= form_open('profile/profile_submit'); ?> 
<table class="table table-hover table-striped table-responsive"> 
    <thead> 
    <tr> 
     <th id="headCheckHide"></th> 
     <th><center>Name</center></th> 
     <th><center>Date of Birth</center></th> 
     <th><center>Occupation</center></th> 
     <th><center>Educ. attainment</center></th> 
    </tr> 
    </thead> 
    <tbody id="sibTable"> 
    <tr class="product-item"> 
      <td> 
       <input type="text" class="form-control form-input" name="siblingName[]"> 
      </td> 
      <td> 
       <input type="text" class="form-control form-input" name="siblingBirthDate[]"> 
      </td> 
      <td> 
       <input type="text" class="form-control form-input" name="siblingOccupation[]"> 
      </td> 
      <td> 
       <select class="form-control form-input" name="siblingEducAttainment[]" > 
       <option value="" selected>-Please select-</option> 
       <option value="less than high school">less than high school</option> 
       <option value="Some college but no degree">Some college but no degree</option> 
       <option value="Associates Degree">Associates Degree</option> 
       <option value="Elementary Graduate">Elementary Graduate</option> 
       <option value="Secondary Graduate">Secondary Graduate</option> 
       <option value="College Graduate">College Graduate</option> 
       <option value="Master's Degree">Master's Degree</option> 
       <option value="Professional Degree">Professional Degree</option> 
       <option value="Doctorate Degree">Doctorate Degree</option> 
       </select> 
      </td> 
     </tr> 
    </tbody> 
</table> 
<?= form_submit('submit','Save', 'class="btn btn-outline-primary waves-effect"');?> 
<?php echo form_close();?> 

Mein Controller für Form

public function profile_submit(){ 
    $siblings=array(

     'name' => $this->input->post('siblingName'), 
     'birthDate' => $this->input->post('siblingBirthDate'), 
     'occupation' => $this->input->post('siblingOccupation'), 
     'educAttainment' => $this->input->post('siblingEducAttainment') 
    ); 

    $this->profile_model->submit_profile($siblings); 
    redirect('profile','refresh'); //name of the html file 
} 

Mein Modell für (profile_model.php)

function submit_profile($siblings){ 
     $this->db->insert('tbl_st_profile_sibling',$siblings); 
} 

Dies ist mein Modell mit dem Fehler: kann Array nicht in die Datenbank einfügen. Kann mir bitte jemand helfen? Danke.

Answer 1

Wenn Sie Array-Daten in der DB speichern müssen, müssen Sie Schleifen verwenden, um eine einzufügen.

function submit_profile($siblings){ 
    foreach($siblings['name'] as $key => $siblingName) { 
     $dataToSave = array(
     'name' => $siblingName, 
     'birthDate' => $siblings['siblingBirthDate'][$key], 
     'occupation' => $siblings['siblingOccupation'][$key], 
     'educAttainment' => $siblings['siblingEducAttainment'][$key] 
    ); 
     $this->db->insert('tbl_st_profile_sibling', $dataToSave); 
    } 
} 

UPDATE: Auch können Sie insert_batch verwenden Einfügung in Schleife überspringen

function submit_profile($siblings){ 
    foreach($siblings['name'] as $key => $siblingName) { 
     $dataToSave[] = array(
     'name' => $siblingName, 
     'birthDate' => $siblings['siblingBirthDate'][$key], 
     'occupation' => $siblings['siblingOccupation'][$key], 
     'educAttainment' => $siblings['siblingEducAttainment'][$key] 
    ); 
    } 
     $this->db->insert_batch('tbl_st_profile_sibling', $dataToSave); 

} 

Answer 2

Das Problem ist nicht mit dem Array, das Sie in der Datenbank speichern, das eigentliche Problem ist mit den Post-Felder Thy sind im Array-Format GeschwisterName []. Sie müssen also in Strings konvertieren, damit dies leicht gespeichert werden kann.

konvertieren Sie das Array in Koma getrennte Liste und dann in der Datenbank speichern.

Answer 3

Ich glaube, Sie mehrere Eingangsdaten zu einer Zeit mit dem gleichen Namen einfügen müssen, keine Sorge, folgen Sie bitte meine Anweisungen wie unten

Änderungen im Steuer gegeben:

public function profile_submit(){ 
    $submit_status = $this->profile_model->submit_profile(); 
    if($submit_status == "TRUE"){ 
    redirect('profile','refresh'); //name of the html file 
    }else{ 
    // Do Something else.. 
    } 

} 

Änderungen im Modell:

function submit_profile(){ 

     $siblingsCount = count($this->input->post('siblingName')); 
     if($siblingsCount != null){ 
     $itemValues=0; 
     $query = "INSERT INTO tbl_st_profile_sibling(name,birthDate,occupation,educAttainment) VALUES "; 
     $queryValue = ""; 
     for($i=0;$i<$siblingsCount;$i++) { 
      $name = $this->input->post('name'); 
      $birthDate = $this->input->post('birthDate'); 
      $occupation = $this->input->post('occupation'); 
      $educAttainment = $this->input->post('educAttainment'); 
      if(!empty($name[$i])) { 
       $itemValues++; 
       if($queryValue!="") { 
        $queryValue .= ","; 
       } 

       $queryValue .= "('" . $name[$i] . "', '" . $birthDate[$i] . "', '" . $occupation[$i] . "', '" . $educAttainment[$i] . "')"; 
      } 
     } 
     $sql = $query.$queryValue; 
     if($itemValues!=0) { 
     if (!$this->db->query($sql)) { 
     echo "FALSE"; 
     }else { 
     echo "TRUE"; 
     } 
     } 
     } 
} 

Ich hoffe, dass dies Ihnen helfen kann ... Danke!

Answer 4

<input type="hidden" name="count" value="<?php echo count($var); ?>" /> 


for($i=0;$i < count($var);$i++) 
{ 

    <tr class="product-item"> 
     <td> 
      <input type="text" class="form-control form-input" name="siblingName<?php echo $i; ?>"> 
     </td> 
     <td> 
      <input type="text" class="form-control form-input" name="siblingBirthDate<?php echo $i; ?>"> 
     </td> 
     <td> 
      <input type="text" class="form-control form-input" name="siblingOccupation<?php echo $i; ?>"> 
     </td> 
     <td> 
      <select class="form-control form-input" name="siblingEducAttainment<?php echo $i; ?>" > 
      <option value="" selected>-Please select-</option> 
      <option value="less than high school">less than high school</option> 
      <option value="Some college but no degree">Some college but no degree</option> 
      <option value="Associates Degree">Associates Degree</option> 
      <option value="Elementary Graduate">Elementary Graduate</option> 
      <option value="Secondary Graduate">Secondary Graduate</option> 
      <option value="College Graduate">College Graduate</option> 
      <option value="Master's Degree">Master's Degree</option> 
      <option value="Professional Degree">Professional Degree</option> 
      <option value="Doctorate Degree">Doctorate Degree</option> 
      </select> 
     </td> 
    </tr> 

} 


$count = $this->input->post('count'); 
for($i=0;$i < $count;$i++) 
{ 
    $siblings=array(
     'name' => $this->input->post('siblingName'.$i), 
     'birthDate' => $this->input->post('siblingBirthDate'.$i), 
     'occupation' => $this->input->post('siblingOccupation'.$i), 
     'educAttainment' => $this->input->post('siblingEducAttainment'.$i) 
    ); 

    $this->profile_model->submit_profile($siblings); 
}