Rearrange-Datensatz

Question

Ich arbeite an einigen Umfragedaten und frage mich, ob ich die Daten neu anordnen könnte, um sie viel brauchbarer zu machen. Die Ergebnisse werden als 1-5 klassifiziert und ich möchte, dass die bevorzugte Tabelle die Ergebnisse nach Wert und Gruppe nach Frage zählt.

Original-Tabelle:

year | month | customer_id | survey | q1 | q2 | q3 | q4 | q5 | q6 ----> q29 
-----|-------|-------------|--------|----|----|----|----|----|--- 
2016 | Oct | ABC12345678 | 1  | 1 | 2 | 3 | 1 | 2 | 3 
2016 | Oct | DEF12345678 | 1  | 2 | 1 | 4 | 2 | 1 | 1 
2016 | Oct | GHI12345678 | 1  | 4 | 2 | 1 | 1 | 3 | 2 
2016 | Oct | JKL12345678 | 1  | 2 | 3 | 2 | 4 | 1 | 3 
2016 | Oct | MNO12345678 | 1  | 5 | 2 | 3 | 1 | 2 | 3 
2016 | Oct | PQR12345678 | 1  | 3 | 4 | 4 | 2 | 4 | 4 
2016 | Oct | STU12345678 | 1  | 1 | 5 | 3 | 1 | 2 | 5 
2016 | Oct | VWX12345678 | 1  | 2 | 2 | 4 | 2 | 1 | 1 

Bevorzugte Tabelle:

Year | Month | Survey | Question | 1 | 2 | 3 | 4 | 5 | 
-----|-------|--------|----------|----|----|----|----|----| 
2016 | Oct | 1 | q1  | 80 | 45 | 25 | 63 | 89 | 
2016 | Oct | 1 | q2  | 65 | 75 | 35 | 53 | 69 | 

Ich kann dies tun mit einer grundlegenden Auswahlabfrage, aber es für jede Frage zu tun, wird sich mit 29 Gewerkschaften beenden und es muss sein ein schneller Weg.

Grüße,

Neil

Answer 1

Dies ist, was ich bis jemand postet eine bessere Lösung verwenden würde:

<!-- language: lang-sql --> 

use tempdb; 
create table #tempsurvey (year int, month varchar(32), customer_id varchar(32), survey int, [q1] int, [q2] int, [q3] int, [q4] int, [q5] int, [q6] int, [q7] int, [q8] int, [q9] int, [q10] int, [q11] int, [q12] int, [q13] int, [q14] int, [q15] int, [q16] int, [q17] int, [q18] int, [q19] int, [q20] int, [q21] int, [q22] int, [q23] int, [q24] int, [q25] int, [q26] int, [q27] int, [q28] int, [q29] int); 
insert into #tempsurvey values (2016,'Oct', 'ABC12345678', 1, 1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2); 
insert into #tempsurvey values (2016,'Oct', 'DEF12345678', 1, 4,5,1,4,5,1,4,5,1,4,5,1,4,5,1,4,5,1,4,5,1,4,5,1,4,5,1,4,5); 

with cte as (
    select t.[year], t.[month], t.customer_id, t.survey, x.question, x.answer 
    from #tempsurvey t 
     cross apply (values ('q1',q1) ,('q2',q2) ,('q3',q3) ,('q4',q4) ,('q5',q5) ,('q6',q6) ,('q7',q7) ,('q8',q8) ,('q9',q9) ,('q10',q10) ,('q11',q11) ,('q12',q12) ,('q13',q13) ,('q14',q14) ,('q15',q15) ,('q16',q16) ,('q17',q17) ,('q18',q18) ,('q19',q19) ,('q20',q20) ,('q21',q21) ,('q22',q22) ,('q23',q23) ,('q24',q24) ,('q25',q25) ,('q26',q26) ,('q27',q27) ,('q28',q28) ,('q29',q29)) 
     as x (Question,Answer) 
) 
    select [year], [month], [survey], question, [1]=sum(case when answer=1 then 1 else 0 end), [2]=sum(case when answer=2 then 1 else 0 end), [3]=sum(case when answer=3 then 1 else 0 end), [4]=sum(case when answer=4 then 1 else 0 end), [5]=sum(case when answer=5 then 1 else 0 end) 
    from cte 
     group by [year], [month], [survey], question; 

    drop table #tempsurvey; 

Brad Schulz auf Kreuz gelten: http://bradsruminations.blogspot.com/search/label/CROSS%20APPLY

Answer 2

Sean korrekt ist. Es wird so gehen:

with subquery as (
    select year, month, survey, question, tempVal from #table 
    unpivot 
    (tempVal for question in (q1, q2, q3, q4, q5, q6, q7, ..., q29)) as up 
) 
select year, month, survey, question, 
    sum(case when tempVal = 1 then 1 else 0 end) as a1, 
    sum(case when tempVal = 2 then 1 else 0 end) as a2, 
    sum(case when tempVal = 3 then 1 else 0 end) as a3, 
    sum(case when tempVal = 4 then 1 else 0 end) as a4, 
    sum(case when tempVal = 5 then 1 else 0 end) as a5 
from subquery 
group by year, month, survey, question