Ich versuche, eine einfache Anmeldeformular django1.11.5 mit erstellen ich ein Projekt mysite mit dem Befehl aufgerufen erstellt:Nameerror: Konto nicht
django-admin.py startproject mysite .
Und ich habe eine App-Konto erstellt genannt die Verwendung von Code:
python manage.py startapp account
In der urls.py Datei des Ordners mysite I angegebene urlto zugegriffen werden, wie folgt:
from django.conf.urls import url, include
from django.contrib import admin
urlpatterns = [
url(r'^account/',include(account.urls)),
url(r'^admin/', admin.site.urls),
]
Allerdings, wenn ich versuche zu migrieren oder runserver bekomme ich den folgenden Fehler.
Unhandled exception in thread started by <function check_errors.<locals>.wrapper at 0x00000273BFBDFC80>
Traceback (most recent call last):
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\utils\autoreload.py", line 228, in wrapper
fn(*args, **kwargs)
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\core\management\commands\runserver.py", line 125, in inner_run
self.check(display_num_errors=True)
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\core\management\base.py", line 359, in check
include_deployment_checks=include_deployment_checks,
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\core\management\base.py", line 346, in _run_checks
return checks.run_checks(**kwargs)
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\core\checks\registry.py", line 81, in run_checks
new_errors = check(app_configs=app_configs)
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\core\checks\urls.py", line 16, in check_url_config
return check_resolver(resolver)
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\core\checks\urls.py", line 26, in check_resolver
return check_method()
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\urls\resolvers.py", line 254, in check
for pattern in self.url_patterns:
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\utils\functional.py", line 35, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\urls\resolvers.py", line 405, in url_patterns
patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\utils\functional.py", line 35, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "C:\Users\Welcome\django\myvenv\lib\site-packages\django\urls\resolvers.py", line 398, in urlconf_module
return import_module(self.urlconf_name)
File "C:\Users\Welcome\AppData\Local\Programs\Python\Python36\lib\importlib\__init__.py", line 126, in import_module
return _bootstrap._gcd_import(name[level:], package, level)
File "<frozen importlib._bootstrap>", line 978, in _gcd_import
File "<frozen importlib._bootstrap>", line 961, in _find_and_load
File "<frozen importlib._bootstrap>", line 950, in _find_and_load_unlocked
File "<frozen importlib._bootstrap>", line 655, in _load_unlocked
File "<frozen importlib._bootstrap_external>", line 678, in exec_module
File "<frozen importlib._bootstrap>", line 205, in _call_with_frames_removed
File "C:\Users\Welcome\django\mysite\urls.py", line 19, in <module>
url(r'^account/',include(account.urls)),
NameError: name 'account' is not defined
So kann jemand bitte helfen. Ich bin neu in diesem
Ist die App "account" in der Einstellung "INSTALLED_APPS" aufgeführt? –
Ja, es ist dort aufgeführt! –