T-SQL-Äquivalent von = rand()

Question

Ich habe mehrere Inhaltstabellen, die ich mit zufälligen Textabsätzen füllen möchte. In MS Word kann ich einfach = rand() und presto! Ich erhalte drei Absätze von druckfrischen Texten.

Gibt es ein SQL-Skript/einen Befehl, mit dem ich zufällige Wörterbuchwörter mit t-sql erzeugen kann?

Answer 1

; 
declare 
    @Lorem nvarchar(max), 
    @RowsToGen int, 
    @Factor int 

select 
    @Lorem = 'Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum.', 
    @RowsToGen = 200 

-- strip punctuations 
set @Lorem = replace(@Lorem, ',', '') 
set @Lorem = replace(@Lorem, '.', '') 

; 
with 
Num1(Pos) as 
(
    select cast(1 as int) 
    union all 
    select cast(Pos + 1 as int) from Num1 where Pos < len(@Lorem) 
), 
Words as 
(
    select substring(@Lorem, Pos, charindex(' ', @Lorem + ' ', Pos) - Pos) as Word 
     from Num1 where Pos <= len(@Lorem) and substring(',' + @Lorem, Pos, 1) = ' ' 
), 
WordsCnt(Factor) as 
(
    select @RowsToGen/count(*) + 1 from Words 
), 
Num2(Pos) as 
(
    select cast(1 as int) 
    union all 
    select cast(Pos + 1 as int) from Num2 cross join WordsCnt where Pos < WordsCnt. Factor 
) 
select top (@RowsToGen) 
    Word 
from 
    Num2 
cross join 
    Words 
order by newid() 
option (maxrecursion 0)  

Answer 2

Es gibt nichts gebaut, aber es ist einfach zu tun:

create table DictionaryWords 
(
    Id int primary key identity (1,1), 
    Word nvarchar(100) not null 
) 
go 

insert DictionaryWords values ('the') 
insert DictionaryWords values ('quick') 
insert DictionaryWords values ('brown') 
insert DictionaryWords values ('fox') 
insert DictionaryWords values ('jumped') 
insert DictionaryWords values ('over') 
insert DictionaryWords values ('the') 
insert DictionaryWords values ('lazy') 
insert DictionaryWords values ('dog') 
go 

create procedure dbo.CreateRandomText(@numWords int, @text nvarchar(max) out) 
as 
begin 

    declare @rowcount int 
    select @rowcount = count(*) from DictionaryWords 

    select @text = '' 

    while @numWords <> 0 
     select @text = @text + ' ' + Word, @numWords = @numWords - 1 
     from DictionaryWords 
     where Id = cast(@rowcount * rand() as integer) 

end 
go 

declare @text nvarchar(max) 
exec CreateRandomText 10, @text out 
select @text 

Answer 3

Hier ist eine andere Version, die einen Satz, statt nur ein einziges Wort pro Zeile gibt, wie von Raj Mehr angefordert.

; 
declare 
    @Lorem nvarchar(max), 
    @SentenceToGen int, 
    @WordsPerSentence int, 
    @Factor int 

select 
    @Lorem = 'Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum.', 
    @SentenceToGen = 200, 
    @WordsPerSentence = 10 

-- strip punctuations 
set @Lorem = replace(@Lorem, ',', '') 
set @Lorem = replace(@Lorem, '.', '') 

; 
with 
Num1(Pos) as -- number of chars in @Lorem 
(
    select cast(1 as int) 
    union all 
    select cast(Pos + 1 as int) from Num1 where Pos < len(@Lorem) 
), 
Words as 
(
    select lower(substring(@Lorem, Pos, charindex(' ', @Lorem + ' ', Pos) - Pos)) as Word 
     from Num1 where Pos <= len(@Lorem) and substring(',' + @Lorem, Pos, 1) = ' ' 
), 
WordsCnt(Factor) as 
(
    select ceiling(cast(@SentenceToGen * @WordsPerSentence as float)/count(*)) from Words 
), 
Num2(Pos) as -- product of words required, to be divided by number of words found in @Lorem 
(
    select cast(1 as int) 
    union all 
    select cast(Pos + 1 as int) from Num2 cross join WordsCnt where Pos < WordsCnt.Factor 
), 
Sentences as 
(
    select 
     ntile(@SentenceToGen) over (order by newid()) as SentenceId, 
     Word 
    from 
     Num2 
    cross join 
     Words 
), 
Num3(Pos) as -- list of SentenceId 
(
    select distinct SentenceId from Sentences 
) 
select 
    (
     select top (@WordsPerSentence) 
      Word + ' ' 
     from 
      Sentences 
     where 
      Sentences.SentenceId = Num3.Pos 
     for xml path('') 
    ) 
    as Sentence 
from 
    Num3  
option (maxrecursion 0)