Erstellen Sie hierarchische XML aus SQL Server-Tabellen

Question

Ich habe eine SQL Server-Datenbank mit 3 Tabellen und ich muss eine XML-Datei mit hierarchischer Struktur aus diesen Tabellen erstellen.

Eine Tabelle enthält Produkte:

ProductID ProductLanguageID ProductDefaultShopID ProductNumber ProductName ProductPrice 
------------------------------------------------------------------------------------------ 
100101@@Inc LANG2    Inc     100101  ABC   159,61 
100102@@Inc LANG2    Inc     100102  BCD   159,61 
100105@@Inc LANG2    Inc     100105  FRE   159,61 
100106@@Inc LANG2    Inc     100106  GDE   159,61 

die zweite hat Gruppen

GroupID  GroupLanguageID GroupName   GroupNumber 
------------------------------------------------------------ 
1@@Inc  LANG2    AAA    1 
1.01@@Inc LANG2    BBB    1.01 
1.02@@Inc LANG2    CCC    1.02 
1.03@@Inc LANG2    DDD    1.03 
1.12@@Inc LANG2    GGG    1.12 

die dritte Sprachen

LanguageID LanguageCode2 LanguageName 
---------------------------------------- 
LANG1  ES    Spain 
LANG2  EN    English 

Ich habe auch 2 Tabellen, die keine Verbindungen haben dont zu weitere Tabellen:

Tabelle

Gruppe Relations

GroupRelationsGroupID GroupRelationsParentID 
-------------------------------------------- 
1.01@@Inc    1@@Inc 
1.02@@Inc    1@@Inc 
1.03@@Inc    1.02@@Inc 
1.12@@Inc    1.03@@Inc 

Group Product Relation Tabelle

GroupProductRelationGroupID GroupProductRelationProductID 
------------------------------------------------------------- 
1.01@@Inc      100101@@Inc 
1.03@@Inc      100102@@Inc 
1.12@@Inc      100105@@Inc 

Die XML-Ausgabe folgende Struktur haben sollte:

<?xml version="1.0" encoding="utf-8"?> 
<root> 
    <productgroup1> 
    <groupname>AAA</groupname> 
    <productgroup2> 
     <groupname>BBB</groupname> 
     <productgroup3> 
     <groupname>CCC</groupname> 
     <products> 
      <product> 
      <itemName>ABC</itemName> 
      <itemNumber>100303</itemNumber> 
      <itemPrice>159.61</itemPrice> 
      <ExtraProductgroup> 
       <extraProductgroupName>GGG</extraProductgroupName> 
       <itemName>FRE</itemName> 
       <itemNumber>100305</itemNumber> 
       <itemPrice>159.61</itemPrice> 
      </ExtraProductgroup> 
      </product> 
     <product> 
      <itemName>BCD</itemName> 
      <itemNumber>100302</itemNumber> 
      <itemPrice>159.61</itemPrice> 
      </product> 
     </products> 
     </productgroup3> 
    </productgroup2> 
    </productgroup1> 
</root> 

Ich kann nur verwenden T-SQL und C# (ASP. Netz Web Forms). HILFE!!! :-)

Answer 1

Ich muss zugeben, dass ich wirklich bezweifle, dass Sie mit dieser Struktur glücklich werden ... Warum sind Produkte unterhalb von groupLevel3, wenn sie mit einer level2-Gruppe verwandt sind? Warum befinden sich ABC und BCD auf demselben Niveau? Wie wird die ExtraGroup gefunden?

Diese Lösung löst nicht alle Daten generisch, bringt aber zumindest das gewünschte Ergebnis mit den gegebenen Daten zurück.

CREATE TABLE #Products(ProductID VARCHAR(50),ProductLanguageID VARCHAR(50),ProductNumber INT, ProductName VARCHAR(50), ProductPrice DECIMAL(14,4)); 
INSERT INTO #Products VALUES 
('100101@@Inc','LANG2',100101,'ABC',159.61) 
,('100102@@Inc','LANG2',100102,'BCD',159.61) 
,('100105@@Inc','LANG2',100105,'FRE',159.61) 
,('100106@@Inc','LANG2',100106,'GDE',159.61) 
; 

CREATE TABLE #Groups(GroupID VARCHAR(50),GroupLanguageID VARCHAR(50),GroupName VARCHAR(50),GroupNumber DECIMAL(5,2)); 
INSERT INTO #Groups VALUES 
('1@@Inc','LANG2','AAA',1) 
,('1.01@@Inc','LANG2','BBB',1.01) 
,('1.02@@Inc','LANG2','CCC',1.02) 
,('1.03@@Inc','LANG2','DDD',1.03) 
,('1.12@@Inc','LANG2','GGG',1.12) 
; 

CREATE TABLE #Languages(LanguageID VARCHAR(50),LanguageCode2 VARCHAR(50),LanguageName VARCHAR(50)); 
INSERT INTO #Languages VALUES 
('LANG1','ES','Spain') 
,('LANG2','EN','English'); 

CREATE TABLE #GroupRelations(GroupRelationsGroupID VARCHAR(50),GroupRelationsParentID VARCHAR(50)); 
INSERT INTO #GroupRelations VALUES 
('1.01@@Inc','1@@Inc') 
,('1.02@@Inc','1.01@@Inc') 
,('1.03@@Inc','1.02@@Inc') 
,('1.12@@Inc','1.03@@Inc'); 

CREATE TABLE #GroupProductRelations(GroupProductRelationGroupID VARCHAR(50),GroupProductRelationProductID VARCHAR(50)); 
INSERT INTO #GroupProductRelations VALUES 
('1.01@@Inc','100101@@Inc') 
,('1.03@@Inc','100102@@Inc') 
,('1.12@@Inc','100105@@Inc'); 


GO 

WITH TopGroups AS 
(
    SELECT gr.GroupID 
    FROM #Groups AS gr 
    WHERE NOT EXISTS(SELECT 1 FROM #GroupRelations AS x WHERE gr.GroupID = x.GroupRelationsGroupID) 
) 
,recGroup AS 
(
    SELECT 1 AS GroupLevel 
      ,g.GroupID 
      ,g.GroupLanguageID 
      ,g.GroupName 
      ,g.GroupNumber 
      ,gr.GroupRelationsParentID AS ParentGroupID 
    FROM #Groups AS g 
    LEFT JOIN #GroupRelations AS gr ON g.GroupID=gr.GroupRelationsGroupID 
    WHERE gr.GroupRelationsParentID IS NULL 
    UNION ALL 
    SELECT prev.GroupLevel + 1 
      ,gNext.GroupID 
      ,gNext.GroupLanguageID 
      ,gNext.GroupName 
      ,gNext.GroupNumber 
      ,grNext.GroupRelationsParentID 
    FROM #GroupRelations AS grNext 
     INNER JOIN #Groups AS gNext ON grNext.GroupRelationsGroupID=gNext.GroupID 
     INNER JOIN recGroup AS prev ON grNext.GroupRelationsParentID=prev.GroupID 
) 
SELECT * 
INTO #tmpFullResult 
FROM recGroup 
LEFT JOIN #GroupProductRelations AS gp ON recGroup.GroupID=gp.GroupProductRelationGroupID 
LEFT JOIN #Products AS p ON gp.GroupProductRelationProductID=p.ProductID 
LEFT JOIN #Languages AS l ON p.ProductLanguageID=l.LanguageID; 

SELECT * FROM #tmpFullResult; 

SELECT lvl1.GroupName AS groupName 
     ,(  
     SELECT lvl2.GroupName AS groupName 
       ,(
       SELECT lvl3.GroupName AS groupName 
        ,(
         SELECT prod.ProductName AS itemName 
           ,prod.ProductNumber AS itemNumber 
           ,prod.ProductPrice AS itemPrice 
           ,(
            SELECT prodExtra.GroupName AS extraProductGroupName 
              ,prodExtra.ProductName AS itemName 
              ,prodExtra.ProductNumber AS itemNumber 
              ,prodExtra.ProductPrice AS itemPrice 
            FROM #tmpFullResult AS prodExtra 
            WHERE prodExtra.ProductID IS NOT NULL 
             AND prodExtra.GroupLevel=5 
            FOR XML PATH('ExtraProductgroup'),TYPE 
           ) 
         FROM #tmpFullResult AS prod 
         WHERE prod.ProductID IS NOT NULL 
          AND prod.GroupLevel<5 
         FOR XML PATH('product'),ROOT('products'),TYPE 
        ) 
       FROM #tmpFullResult AS lvl3 
       WHERE lvl3.GroupLevel=3 AND lvl3.ParentGroupID=lvl2.GroupID 
       FOR XML PATH('productGroup3'),TYPE 
       ) 
     FROM #tmpFullResult AS lvl2 
     WHERE lvl2.GroupLevel=2 AND lvl2.ParentGroupID=lvl1.GroupID 
     FOR XML PATH('productGroup2'),TYPE 
     ) 
FROM #tmpFullResult AS lvl1 
WHERE lvl1.ParentGroupID IS NULL 
FOR XML PATH('productgroup1'),ROOT('root') 
GO 
DROP TABLE #tmpFullResult; 
DROP TABLE #GroupProductRelations 
DROP TABLE #Groups 
DROP TABLE #GroupRelations 
DROP TABLE #Languages 
DROP TABLE #Products 

Das Ergebnis

<root> 
    <productgroup1> 
    <groupName>AAA</groupName> 
    <productGroup2> 
     <groupName>BBB</groupName> 
     <productGroup3> 
     <groupName>CCC</groupName> 
     <products> 
      <product> 
      <itemName>ABC</itemName> 
      <itemNumber>100101</itemNumber> 
      <itemPrice>159.6100</itemPrice> 
      <ExtraProductgroup> 
       <extraProductGroupName>GGG</extraProductGroupName> 
       <itemName>FRE</itemName> 
       <itemNumber>100105</itemNumber> 
       <itemPrice>159.6100</itemPrice> 
      </ExtraProductgroup> 
      </product> 
      <product> 
      <itemName>BCD</itemName> 
      <itemNumber>100102</itemNumber> 
      <itemPrice>159.6100</itemPrice> 
      <ExtraProductgroup> 
       <extraProductGroupName>GGG</extraProductGroupName> 
       <itemName>FRE</itemName> 
       <itemNumber>100105</itemNumber> 
       <itemPrice>159.6100</itemPrice> 
      </ExtraProductgroup> 
      </product> 
     </products> 
     </productGroup3> 
    </productGroup2> 
    </productgroup1> 
</root>