Ich habe einige kleine Änderungen machen diese Aktion mit jquery auszuführen
<body>
<table cellspacing="2" cellpadding="2" border="2">
<?php $sql = "Select * from prject_topic"; $result = mysqli_query($conn, $sql);
while($row = mysqli_fetch_assoc($result)) { ?>
<tr>
<td><?php echo $row['lecturer_name'];?></td>
<td><?php echo $row['topic'];?></td>
<td><span class="actu" id="<?php echo $row['project_id'];?>">
<?php echo $row['status'];?>
</span>
</td>
</tr> <?php } ?>
</table>
<script type="text/javascript">
$(function(){
//We capture the Click in the user item
$(".actu").on('click', function(){
//We take the ide of this item
var id = $(this).attr('id');
//We check the current status of the user
if($(this).html() == "Deactivate"){
var est = "Activate";
}else{
var est = "Deactivate";
}
//We made a request of type ajax sending by post the id for its update
$.post('#.php',
{
'id':id,
'est':est
},
//We received the response from our php file which may be a code as in the example...
function(data){
if(data=="200"){
//If yes, update the content of the selected item in real time
$("#"+id).html('Deactivate');
}else{
//In case of error, we send the information
alert("Unable to disable user");
}
})
})
})
</script>
</body>
Der Code ist für Ihr Verständnis geschrieben
Vielen Dank Carlos Quintero. Pls können Sie mir mit dem vollständigen Skript helfen? – nwafeolie
Ok mir Ihren Code senden Sie es Php $ sql = "select * from prject_topic" –