Nach jupyterjupyter Notebook nicht auf Mac laufen
$ jupyter notebook
Ich laufe nicht jupyter-Notebook correctly.The Fehler ich erhalte, ist installieren pip:
Traceback (most recent call last): File "/usr/local/bin/jupyter-notebook", line 11, in <module> sys.exit(main()) File "/Library/Python/2.7/site-packages/jupyter_core/application.py", line 267, in launch_instance return super(JupyterApp, cls).launch_instance(argv=argv, **kwargs) File "/Library/Python/2.7/site-packages/traitlets/config/application.py", line 657, in launch_instance app.initialize(argv) File "<decorator-gen-7>", line 2, in initialize File "/Library/Python/2.7/site-packages/traitlets/config/application.py", line 87, in catch_config_error return method(app, *args, **kwargs) File "/Library/Python/2.7/site-packages/notebook/notebookapp.py", line 1071, in initialize self.init_webapp() File "/Library/Python/2.7/site-packages/notebook/notebookapp.py", line 919, in init_webapp self.http_server.listen(port, self.ip) File "/Library/Python/2.7/site-packages/tornado/tcpserver.py", line 126, in listen sockets = bind_sockets(port, address=address) File "/Library/Python/2.7/site-packages/tornado/netutil.py", line 153, in bind_sockets 0, flags)): socket.gaierror: [Errno 4] Non-recoverable failure in name resolution
Welche Version von Jupyter Notebook laufen Sie? – rtk22
@ rtk22 Version 4.2.0 – flyingpot
Versuchen Sie 'jupyter notebook --ip = 127.0.0.1' und wenn das scheitert dann' jupyter notebook --ip = 0.0.0.0' – rtk22