Hier gehen wir mit einer Idee:
import java.util.Scanner;
public class ScannerTest {
private Scanner consoleScanner;
public ScannerTest() {
consoleScanner = new Scanner(System.in);
}
@SuppressWarnings("unchecked")
private <T extends Number> T readType(String description, Class<T> desiredType) {
System.out.println(description);
Number result = null;
while (result == null) {
System.out.println();
System.out.print("Choose one: ");
try {
if (Integer.class.equals(desiredType)) {
result = new Integer(consoleScanner.nextInt());
} else if (Long.class.equals(desiredType)) {
result = new Long(consoleScanner.nextLong());
}
} catch(Exception e) {
consoleScanner.nextLine();
}
}
consoleScanner.nextLine();
return (T) result;
}
public long readLong(String description) {
return this.readType(description, Long.class);
}
public int readInt(String description) {
return this.readType(description, Integer.class);
}
public static void main(String[] args) {
ScannerTest t = new ScannerTest();
t.readLong("Reading a long value...");
t.readInt("Reading an integer value...");
}
}
aktualisieren nach @ Michu93 Idee einer einzigen transparenten Methode:
import java.util.Scanner;
public class ScannerTest {
private Scanner consoleScanner;
public ScannerTest() {
consoleScanner = new Scanner(System.in);
}
@SuppressWarnings("unchecked")
public <T extends Number> T readNumber(String description) {
System.out.println(description);
Number result = null;
while (result == null) {
System.out.print("\nChoose one: ");
String textRead = consoleScanner.next();
try {
result = new Integer(textRead);
} catch(Exception e1) {
try {
result = new Long(textRead);
} catch (Exception e2) {
try {
result = new Double(textRead);
} catch (Exception e3) {
}
}
}
consoleScanner.nextLine();
}
return (T) result;
}
public static void main(String[] args) {
ScannerTest t = new ScannerTest();
for (int i = 0; i < 3; i++) {
Number input = t.readNumber(i + ": Reading int, long or double...");
System.out.println("Input class: " + input.getClass().getCanonicalName());
System.out.println("Input value: " + input);
}
}
}
Beitrag dieser Frage auf [Code-Review] (https://codereview.stackexchange.com/). –
Werfen Sie einen Blick auf generische Typen in Java – Michu93
Wie weiß der Aufrufer dieser Methoden, welchen Aufruf er ausführen soll? –