Android HttpUrlConnection funktioniert nicht richtig

Question

Ich habe versucht, einige Informationen von einer Android-Anwendung mit der HttpUrlConnection zu einem PHP-Skript online zu senden. Ich bin zu beiden PHP sehr neu und habe die HttpUrlConnection vorher nie benutzt, also bin ich ziemlich fest, warum das nicht funktioniert. Es werden auch keine Fehler ausgelöst.

mein PHP-Skript ist

<?php 

//get connection details from the app and then connect to db 
$db_host = $_POST['db_host']; 
$db_user = $_POST['db_user']; 
$db_pass = $_POST['db_pass']; 
$db_name = $_POST['db_name']; 

$con = mysqli_connect($db_host, $db_user, $db_pass, $db_name); 

if (!$con) { 
    die("Connection failed: " . mysqli_connect_error()); 
} 

$device_group_id = $_POST['device_group_id']; 

//create the new device group as a table in the database 
$create_table_query = "CREATE TABLE" . $device_group_id . "(
     device_id varchar(24), 
     device_alias varchar(24), 
     device_longitute int, 
     device_latititute int, 
     device_group_id varchar(24) 
)"; 

if (mysqli_query($con, $create_table_query)) { 
    echo "Table MyGuests created successfully"; 
} else { 
    echo "Error creating table: " . mysqli_error($con); 
} 

mysqli_close($con); 

?> 

und die AsyncTask Methode doInBackground() ist

@Override 
protected Object doInBackground(Object[] params) { 
    String result = ""; 
    try{ 
     //get values to pass to the PHP script 
     Pair<String, String> dbHost = new Pair<>("db_host", DbConnectionInfo.DB_HOST); 
     Pair<String, String> dbUser = new Pair<>("db_user", DbConnectionInfo.DB_USER); 
     Pair<String, String> dbPass = new Pair<>("db_pass", DbConnectionInfo.DB_PASS); 
     Pair<String, String> dbName = new Pair<>("db_host", DbConnectionInfo.DB_NAME); 
     Pair<String, String> deviceGroupId = new Pair<>("device_group_id", "new_device_group"); 

     URL url = new URL("http://tracme.net16.net/create_device_group.php"); 
     HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection(); 

     // prepare request 
     urlConnection.setRequestMethod("POST"); 
     urlConnection.setDoInput(true); 
     urlConnection.setDoOutput(true); 
     urlConnection.setReadTimeout(10000); 
     urlConnection.setConnectTimeout(15000); 
     urlConnection.setChunkedStreamingMode(0); 

     //upload request 
     OutputStream outputStream = urlConnection.getOutputStream(); 
     OutputStreamWriter writer = new OutputStreamWriter(outputStream, "UTF-8"); 
     writer.write(dbHost.first + "=" + dbHost.second); 
     writer.write(dbUser.first + "=" + dbUser.second); 
     writer.write(dbPass.first + "=" + dbPass.second); 
     writer.write(dbName.first + "=" + dbName.second); 
     writer.write(deviceGroupId.first + "=" + deviceGroupId.second); 
     writer.close(); 
     outputStream.close(); 

     // read response 
     BufferedReader in = new BufferedReader(
       new InputStreamReader(urlConnection.getInputStream())); 

     String inputLine; 
     StringBuffer response = new StringBuffer(); 
     while ((inputLine = in.readLine()) != null) { response.append(inputLine); } 
     in.close(); 

     result = response.toString(); 

     // disconnect 
     urlConnection.disconnect(); 

    }catch(MalformedURLException e) { 
     Log.e("Malformed URL Exception", "Malformed URL Exception"); 
    }catch (IOException e) { 
     Log.e("IOException", "IOException"); 
    } 

    return result; 
} 

Answer 1

In Ihrem Code:

$device_group_id = $_POST['device_group_id']; 

//create the new device group as a table in the database 
$create_table_query = "CREATE TABLE" . $device_group_id . "(
    device_id varchar(24), 
    device_alias varchar(24), 
    device_longitute int, 
    device_latititute int, 
    device_group_id varchar(24) 
)"; 
mysqli_close($con); 

Sie sind nur einen vairable Namen erstellen $create_table_query die hält nur die Abfrage. Es gibt keinen Code, der die Abfrage tatsächlich ausführt. Fügen Sie diesen Code vor mysqli_close($con);

if ($con->query($create_table_query) === TRUE) { 
    echo "<br>Table created<br>"; 
} else { 
    echo "<br>Error creating table: " . $con->error. "<br>"; 
}