Kumulative Mittelwerte berechnen (Wie mache ich das?)

Question

Ich habe drei Funktionen, eine für die Berechnung des Labordurchschnitts, eine für die gewichtete Punktzahl und eine für den Programmdurchschnitt. Diese Funktionen berechnen die Punktzahlen eines bestimmten Schülers, den der Benutzer auswählt. (Für ex. Wird Labor avg berechnen. Für nur Ablao nicht andere Studenten)

Ablao 3 74 96 72 88 71 80 83 77 90 88 95 71 76 94 80 74 98 77 
Anderson 3 76 92 98 95 92 76 93 97 85 76 85 93 82 88 75 84 92 77 
Aspinwall 1 86 74 78 97 86 94 73 95 74 91 75 94 83 99 83 78 88 96 
Bacon 4 72 95 81 80 89 88 100 87 87 81 79 77 75 83 87 96 72 95 

Es Informationen für 60 Schüler in der Datei ist. Die erste Zahl nach dem Namen steht für die Note des Schülers. 1 = Freshman 2 = Sophomore usw.

Ich muss eine neue Funktion erstellen, die meine vorhandenen Funktionen verwenden wird, um die Durchschnittswerte aller Studenten zusammen zu berechnen, und der Schüler für jede Klasse und dann diese Durchschnittswerte, finden Sie die max und min.

Der Code, den ich bisher für diese Funktion geschrieben habe, funktioniert nicht und ich weiß nicht, wie ich mich dem Problem nähern soll.

with open(FileName, 'r') as f: 
    line = f.readlines() 

student_status=(float(line.split()[1])) 

def make_lists_of_status(): 
    if (student_status==1): 
     Freshman.append(student_scores) 
    elif (student_status==2): 
     Sophomores.append(student_scores) 
    elif (student_status==3): 
     Juniors.append(student_scores) 
    elif (student_status==4): 
     Seniors.append(student_scores) 

Erwartete Ausgabe sollte

This option is for viewing statistics sorted by the year of student. 
    Please select one of the following options: 
    a for ALL YEARS 
    b for FRESHMAN 
    c for SOPHMORES 
    d for JUNIORS 
    e for SENIORS 

Enter your choice here: e 

For Seniors: 
High/Low/Mean of all Weighted Scores: 89.53999999999999/ 81.60000000000001/86.15736842105264 
High/Low/Mean of all Lab Averages: 89.6/80.2/86.21052631578948 
High/Low/Mean of all Program Averages: 94.33333333333333/77.0/86.78947368421052 

Answer 1

wie sein Dies kann mit einem Wörterbuch durchgeführt werden.

students = {} 

with open("inCSV.txt", "r") as f: 
    for line in f.readlines(): 
     data = line.rstrip().split(" ") 

     student_name = data[0] 
     student_grade = data[1] 
     student_data = [int(x) for x in data[2:]] 
     student_avg = sum(student_data[2:])/float(len(student_data[2:])) 

     # Set the students name to a tuple of student's grade and average 
     students[student_name] = (student_grade, student_avg) 

# Sort the students by their averages. (Descending order) 
# Add reverse=True to have it in ascending order 
print sorted(students.keys(), key=lambda x: students[x][1]) 

EDIT

Es ist immer noch in einer ähnlichen Art und Weise durchgeführt werden kann.

students = {} 

def weighted_scores(x): 
    return x 

with open("inCSV.txt", "r") as f: 
    for line in f.readlines(): 
     data = line.rstrip().split(" ") 

     student_name = data[0] 
     student_grade = data[1] 
     student_data = [int(x) for x in data[2:]] 

     student_program_avg = sum(student_data[2:])/float(len(student_data[2:])) 
     # Edit this part to your code 
     student_weighted_scores = weighted_scores(data[2:]) 
     student_lab_averages = lab_average(data[2:]) 

     students[student_name] = (student_grade, 
            student_weighted_scores, 
            student_lab_averages, 
            student_program_avg) 
print students 

def get_level(x): 
    ret_dict = {} 
    for k, v in students: 
     if v[0] == x: 
      ret_dict[k] = v 


def choose(x): 
    people = get_level(x) 
    overall = [] 

    for s in range(1, 4): 
     # Get grades of either weighted scores, lab averages or just average. 
     # Sort grades in descending order 
     grades = sorted(people.keys(), key=lambda x: people[x][s]) 

     highest = grades[0] 
     lowest = grades[-1] 
     mean = sum(grades[2:])/float(len(grades[2:]) 

     overall.append((highest, lowest, mean)) 

    # overall[0] => weighted scores 
    # overall[1] => lab averages 
    # overall[2] => program average 
    # overall[x][0] => highest of x 
    # overall[x][1] => lowest of x 
    # overall[x][2] => mean of x 

    print "For %i level:" % (x) 
    print "High/Low/Mean of Weighted Scores: %i/%i/%i" % (overall[0][0], overall[0][1], overall[0][2]) 
    print "High/Low/Mean of Lab Averages: %i/%i/%i" % (overall[1][0], overall[1][1], overall[1][2]) 
    print "High/Low/Mean of Weighted Scores: %i/%i/%i" % (overall[2][0], overall[2][1], overall[2][2]) 

# Let's say you picked seniors: 
choose(4) 

Answer 2

Ich denke, das tut, was Sie wollen:

scores_student = {} 
scores_grade = [[],[],[],[]] 
scores_all  = [] 
with open("students.txt", "r") as f: 
    for line in f: 
     # Parse the line 
     toks = line.split() 
     name = toks[0] 
     grade = int(toks[1]) 
     scores = [float(tok) for tok in toks[2:]] 
     # Save scores both per student, in that student's grade, and total 
     scores_student[(name,grade)] = scores 
     scores_grade[grade-1] += scores 
     scores_all += scores 

# Print individual student info 
print "Students" 
for name,grade in sorted(scores_student): 
    score = scores_student[(name,grade)] 
    print "%-10s %d mean %4.1f max %3d min %3d" % (name, grade, sum(score)/len(score), max(score), min(score)) 
print 
print "Summary" 
for grade, score in enumerate(scores_grade): 
    if len(score) > 0: 
     print "grade %d mean %4.1f max %3d min %3d" % (grade+1, sum(score)/len(score), max(score), min(score)) 
print "all  mean %4.1f max %3d min %3d" % (sum(scores_all)/len(scores_all), max(scores_all), min(scores_all))